Answer:your question seems incomplete but if you looking to find the resulting equation to solve for temperature at a particular time you can use this 28t^2
Step-by-step explanation:
F'(t) = 7(0.8)t
Integrating the RHS
Temp= integral of f'(t)= 28t^2
Therefore, T(°c)= 28t^2
(y2-y1)/(x2-x1) (-3 - (-8))/(6- (-5))= 5/11
The value will be positive
since the slope is going upwards
The answer is is 24 5 +9=15+9=24
Answer:
zero
Step-by-step explanation:
zero graphs are lines that are horizontal.
