Answer:
4
Step-by-step explanation:
Let y be the width of the rectangle
The length of the rectangle is 5 unit more than the width. This is written as:
Length = y + 5
Area = 36
Recall:
Area of rectangle = length x width
36 = (y + 5) x y
36 = y^2 + 5y
Rearrange the expression
y^2 + 5y — 36 = 0
To solve this problem by factorization, multiply the first term (i.e y^2) and last term ( i.e — 36) together. This gives — 36y^2
Next, find two factors of —36y^2 such that when we add them together it will result to the second term (5y). These factors are —4y and 9y. Now we substitute —4y and 9y in place of 5y in the equation. This is illustrated below:
y^2 + 5y — 36 = 0
y^2 —4y + 9y — 36 = 0
We factorize as follows:
y(y — 4) + 9(y —4) = 0
(y + 9) (y — 4) =0
y + 9 = 0 or y — 4 = 0
y = —9 or y = 4
Since the measurement can not be negative, therefore y (i.e the width) is 4
First find the length of all the sides.
Then divide that polygon (if it has more than 4 sides or an irregular quadrilateral) into triangles.
Find the area of triangles so formed by Heron's formula.
Than sum the area of all the triangles. The sum will be the area of the polygon.
Answer:
q < 56
Step-by-step explanation:
q + 12 - 2(q - 22) > 0
q + 12 - 2q + 44 > 0
-q + 56 > 0
+q +q
56 > q
Answer:
y = - 0.5
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Answer:
Depending on what you're looking for: 5 or -5/2
Step-by-step explanation:
If non-function, count the height in which it covers: 5
If function, find slope (rise over run): -5/2
