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3 years ago

13

What are the solutions to the quadratic equation 2x^2-8x-24=0

2 answers:

DENIUS [597]3 years ago

8 0

2x^2-8x-24=0
Divide the whole equation by 2.
x^2-4x-12=0
Complete the square
x^2-4x+4-16=0
(x-2)^2 -16=0
(x-2)^2=16
Take the square root of each side.
(x-2)=4 and (-(x-2))=4
x=6 and x=-2

Crank3 years ago

6 0

An easy formula to use for this is -b+-√b^2-4(a×c)] /2(a) . This gave me ;

8+-√-8^2-4(2(-24)) /2(2)

8+-√64-4(-48)/4

8+-√64+192]/4

8+-√256]/4

8+-16/4

8+16=24/4=6

8-16=-8/4=-2

X=6&-2

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3 years ago

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

2 years ago

17. Simplify (3 × 22) ÷ 6 + [28 – (4)2] = ?

Effectus [21]

Answer:

31

Step-by-step explanation:

(3*22=66) / 6 + [28n - (4)2=20]

66 /6 = 11+ [20]

11+20= 31

7 0

3 years ago

The area of these shapes are?

kipiarov [429]

Answer:
Figure 1:
Area = 390ft^2

Figure 2:
Area = 325.17 ft^2

7 0

3 years ago

Identify an equation in slope intercept form for the line parallel to y= -2/3x+8 that passes through (4, -5)

Evgen [1.6K]

Answer:

3y = -2x -7

Step-by-step explanation:

The equation of the line;

y = $-\frac{2}{3}$ x + 8

Unknown:

Equation of the line passing through (4, -5);

Solution:

To solve this problem;

the equation of a line is given as;

y = mx + c

where x and y are the coordinate

m is the slope

c is the intercept

To solve this problem,

The slope $-\frac{2}{3}$ if the same as that of the new line since they are parallel;

Equation of the new line;

x = 4 and y = -5

-5 = $-\frac{2}{3}$ x 4 + c

-5 = $-\frac{8}{3}$ + c

c = -5 + $\frac{8}{3}$

c = $-\frac{7}{3}$

So, the equation of the line is;

y = $-\frac{2}{3}$ x - $\frac{7}{3}$

or ;

3y = -2x -7

7 0

3 years ago