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Gemiola [76]
3 years ago
13

What are the solutions to the quadratic equation 2x^2-8x-24=0

Mathematics
2 answers:
DENIUS [597]3 years ago
8 0
2x^2-8x-24=0
Divide the whole equation by 2.
x^2-4x-12=0
Complete the square
x^2-4x+4-16=0
(x-2)^2 -16=0
(x-2)^2=16
Take the square root of each side.
(x-2)=4 and (-(x-2))=4
x=6 and x=-2
Crank3 years ago
6 0
An easy formula to use for this is -b+-√b^2-4(a×c)] /2(a) . This gave me ;

8+-√-8^2-4(2(-24)) /2(2)

8+-√64-4(-48)/4

8+-√64+192]/4

8+-√256]/4

8+-16/4

8+16=24/4=6

8-16=-8/4=-2

X=6&-2
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Can someone please help me with this? It would be greatly appreciated:) thanks
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Answer:

d < 1

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2 years ago
What is the value of x?
statuscvo [17]

x = 16.

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A rectangle is such that the length of 2 of each adjacent sides are in the ratio 1:3. A similar rectangle has 1 side of 6cm. Fin
Sliva [168]

Answer:

18 cm ;

2 cm

Step-by-step explanation:

Length of each adjacent side = 1 :3

If 1 side = 6 ; the possible values of the adjacent side ;

That is side 2 ÷

If side 1, which is 6cm is the ratio 1 ; then side 2 = 6cm * 3 = 18 cm

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