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MrMuchimi
2 years ago
13

PLEASE HELP !!!!! 2 - 19 = 2? BTW BTS OUTSOLD AND PAVED THE WAY !!!!!!!!!!

Mathematics
2 answers:
Ede4ka [16]2 years ago
5 0

Answer:

its not true the answer is -17 i dont know if thats what your looking for

Step-by-step explanation:

lawyer [7]2 years ago
5 0
That’s wrong it’s -17. 2 is not the answer
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Select expression that is mathematically equivalent to xy−z+ (a - b) X c. y - 2 O
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Question:

Select expression that is mathematically equivalent to

\frac{x}{y-z} + (a-b)*c

a) x/y - z + (a - b) * c

b) x/(y - z) + (a - b) * c

c) x/y - z + a - b * c

d) x/(y - z) + a - b * c

Answer:

x/(y - z) + (a - b) * c

Step-by-step explanation:

Given

\frac{x}{y-z} + (a-b)*c

Required

Determine its equivalent

Start by writing y - z in bracket;

\frac{x}{y-z} + (a-b)*c

becomes

\frac{x}{(y-z)} + (a-b)*c

When - is used as divide, it is equivalent to /

The given expression can then be rewritten as

x/(y - z) + (a - b) * c

Hence;

<em />\frac{x}{y-z} + (a-b)*c<em> is equivalent to </em>x/(y - z) + (a - b) * c<em />

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3 years ago
Which of the following tables can be generated from the equation y equals 2x + 1​
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Answer: 2 the first one

Step-by-step explanation:

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Mr.Reddrick has a 74 total yards of red and blue felt to distribute to students in his art class. Each of his 20 students gets 2
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Answer:

A. 1.2 yd

Step-by-step explanation:

We are informed that Mr.Reddrick has a 74 total yards of red and blue felt to distribute to students in his art class. Moreover, we also have the information that each of his 20 students gets 2.5 yards of blue felt for the project. This implies that the total blue felt distributed is;

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Since we have 20 students, each one of them receives;

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How many different 10-letter words can be formed from the following letters? V, Y,G,U,E,H,Y,M,L,I
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Answer:

Problems like this all have the same solution method.

If you have n letters, you start with n!. Then you divide by k! for each distinct set of k letters.

This is purely mechanical. E.g., if you have

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Once you know that, these problems are really, really easy.

ion:

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