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pashok25 [27]
2 years ago
6

The data in the table shows a sinusoidal relationship between the number of seconds an object has been moving and its velocity v

(x), measured in centimeters per second
What is true of the cosine function that models the data in the table?
Drag a value into each box to correctly complete the statements.

The period of the cosine function is The equation of the midline of the cosine function is y = 20 The amplitude of the cosine function is ​

Mathematics
1 answer:
OlgaM077 [116]2 years ago
5 0

Answer:

The period is the change in x required for the function to return to the same value, changing in the same direction. The first two table entries are v(x) = 41.7 and 35.7. The next time that sequence appears is when x=44, so the period is ...

 period = 44 -4 = 40 . . . seconds

__

The minimum table value is 20; the maximum is 44, so the midline of the function is their average:

 midline = (20 +44)/2 = 32

__

The amplitude is the maximum deviation from the midline, so is ...

 amplitude = 44 -32 = 12

Step-by-step explanation:

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Solve the system of linear equations by substitution. x=16−4y 3x+4y=8
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Answer:

Solution: (-4,5)

Step-by-step explanation:

x=16-4y

3x+4y=8

-----

The 1st equation tells you x = 16-4y

---

Substitute that into the 2nd equation

and solve for "y":

3(16-4y)+4y = 8

48 - 12y + 4y = 8

-8y = -40

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y = 5

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2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):
zlopas [31]
<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)

First pair of opposite sides:

<u>Slope:</u>

\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}

Second pair of opposite sides:

<u>Slope:</u>

\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\

So the diagonals measure the same, therefore this is a rectangle.

5 0
4 years ago
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