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juin [17]
4 years ago
9

What’s the value for x? please help

Mathematics
1 answer:
Mila [183]4 years ago
5 0

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>

<h3><em>Follow </em><em>me</em><em> </em><em>for</em><em> </em><em>more</em><em>.</em></h3>

<em>-pragya~</em><em>~</em>

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77julia77 [94]

Answer:

Step-by-step explanation:

The answers are F,A,

3 0
4 years ago
What is the answer for 4x + 7x
NikAS [45]

Answer:

11x

Step-by-step explanation:

All you can do in this situation is simplify the equation

4x+7x= 11x

8 0
3 years ago
What is the sum for quadrilateral ​
mihalych1998 [28]

Answer:

360 degrees

Step-by-step explanation:

The sum of all interior angles in a quadrilateral is 360 degrees.

8 0
3 years ago
Calculate 0.82 + 0.35 ?
natima [27]

ANSWER

EXPLANATION

We want to add the two numbers:

0.82 + 0.35

Using the long addition method, we have:

0 . 8 2

+ 0 . 3 5

Start on the right hand side:

4 0
2 years ago
A study was conducted to determine whether there were significant differences between medical students admitted through special
Mekhanik [1.2K]

Answer:

P(X\geq 9)=P(X=9)+P(X=10)

And using the probability mass function we got:

P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383  

P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402  

And replacing we got:

P(X \geq 9) = 0.383 +0.402= 0.785

Step-by-step explanation:

Let X the random variable of interest "number of  students graduated", on this case we now that:  

X \sim Binom(n=10, p=0.913)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X\geq 9)=P(X=9)+P(X=10)

And using the probability mass function we got:

P(X=9)=(10C9)(0.913)^9 (1-0.913)^{10-9}=0.383  

P(X=10)=(10C10)(0.913)^{10} (1-0.913)^{10-10}=0.402  

And replacing we got:

P(X \geq 9) = 0.383 +0.402= 0.785

3 0
4 years ago
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