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finlep [7]
3 years ago
7

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS IF YOU ANSWER WITH A LINK YOU WILL GET REPORTED!!!!!!

AND EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0

Answer:

1,5

Step-by-step explanation:

The translation can be seen in one line. You can see one going up by 5 and going to the right (not left as that would make it -1,5).

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HELP 30 POINTS WILL GIVE BRAINLIEST
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×imagine this is a flattened pyramid box. When you fold along the dotted lines you can see which sides are equivalent.

Add up the areas of each piece.

Two identical rectangular pieces 7 × 10
2(7)(10) = 140

One small rectangular piece 6 × 7
7(6) = 42

Two identical triangles
2(0.5)(6)(8) = 48

Add up all the pieces
140 + 42 + 48 = 230

3 0
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Winston needs at least 80 signatures from students in his school before he can run for class president. He has 23 signatures alr
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Answer:

Step-by-step explanation:

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3 years ago
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Consider the points A(5, 3t+2, 2), B(1, 3t, 2), and C(1, 4t, 3). Find the angle ∠ABC given that the dot product of the vectors B
Vilka [71]

Answer:

66.42°

Step-by-step explanation:

<u>Given:</u>

A(5, 3t+2, 2)

B(1, 3t, 2)

C(1, 4t, 3)

BA • BC = 4

Step 1: Find t.

First we have to find vectors BA and BC. We do that by subtracting the coordinates of the initial point from the coordinates of the terminal point.

In vector BA B is the initial point and A is the terminal point.

BA = OA - OB = (5-1, 3t+2-3t, 2-2) = (4, 2, 0)

BC = OC - OB = (1-1, 4t-3t, 3-2) = (0, t, 1)

Now we can find t because we know that BA • BC = 4

BA • BC = 4

To find dot product we calculate the sum of the produts of the corresponding components.

BA • BC = (4)(0) + (2)(t) + (0)(1)

4 = (4)(0) + (2)(t) + (0)(1)

4 = 0 + 2t + 0

4 = 2t

2 = t

t = 2

Now we know that:

BA = (4, 2, 0)

BC = (0, 2, 1)

Step 2: Find the angle ∠ABC.

Dot product: a • b = |a| |b| cos(angle)

BA • BC = 4

|BA| |BC| cos(angle) = 4

To get magnitudes we square each compoment of the vector and sum them together. Then square root.

|BA| = \sqrt{4^2 + 2^2 + 0^2} = \sqrt{20} = 2\sqrt{5}

|BC| = \sqrt{0^2 + 2^2 + 1^2} = \sqrt{5}

2\sqrt{5}\sqrt{5}\cos{(m\angle{ABC})} = 4

10\cos{(m\angle{ABC})} = 4

\cos(m\angle{ABC}) = \frac{4}{10}=\frac{2}{5}

m\angle{ABC} = cos^{-1}{(\frac{2}{5})}

m\angle{ABC} = 66.4218^{\circ}

Rounded to two decimal places:

m\angle{ABC} = 66.42^\circ

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2 years ago
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A rectangular prism has a base with a length of 25, a width of 9, and a height of 12. A second prism has a square base with a si
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Answer:

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Volume= 15^2 x\\2700/225=x\\12=x

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