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larisa86 [58]
3 years ago
12

~!!!!HELPPPPPPP IM IN 7TH GRADE LEARNING 9TH AND 8TH GRADE MATH !!!!~

Mathematics
1 answer:
const2013 [10]3 years ago
4 0

Answer:

See below.

Step-by-step explanation:

You don't show what the function is, but I'll explain how to do it.

The average rate of change of function f(x), from x = a to x = b, is given by the fraction:

\dfrac{f(b) - f(a)}{b - a}

Since I don't know what the function is, I cannot evaluate the function at x = a and at x = b, which in your case are x = 2 and x = 3, but you can do it.

Here are the steps you need to do:

1) Evaluate the function at x = 3. Get a value for f(3).

2) Evaluate the function at x = 2. Get a value for f(2).

3) Evaluate the following fraction, after writing the values for f(3) and f(2) that you found in steps 1) and 2) above.

\dfrac{f(3) - f(2)}{3 - 2}

The denominator above is easy. It's just 1.

Try it and see what you get. You can write the function and your answer in the comments if you need more help.

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KatRina [158]

Answer:

D.96ft^3......is the and...hope it helps

3 0
3 years ago
What are the domain and range of the function f(x) = 3x + 5
fredd [130]

Step-by-step explanation:

Here,let x = 1,2,3 and 4

Then,

Domain =(1,2,3,4)

Again,

f(1)= 3*1 + 5

=3 + 5

=8

f(2)=3*2 + 5

=6 + 5

=11

f(3)=3*3 + 5

=9 + 5

=14

f(4)=3*4 + 5

=12 + 5

=17

Therefore, Range=(8,11,14,17)

7 0
2 years ago
Use the quadratic formula to solve x^2+8x+9=0
Tju [1.3M]
None of your options, not via complete the square nor quadratic the formula.

Solve for x over the real numbers:
x^2 + 8 x + 9 = 0

x = (-8 ± sqrt(8^2 - 4×9))/2 = (-8 ± sqrt(64 - 36))/2 = (-8 ± sqrt(28))/2:
x = (-8 + sqrt(28))/2 or x = (-8 - sqrt(28))/2

sqrt(28) = sqrt(4×7) = sqrt(2^2×7) = 2sqrt(7):
x = (2 sqrt(7) - 8)/2 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 + 2 sqrt(7) giving 2 (sqrt(7) - 4):
x = 1/22 (sqrt(7) - 4) or x = (-2 sqrt(7) - 8)/2

(2 (sqrt(7) - 4))/2 = sqrt(7) - 4:
x = sqrt(7) - 4 or x = (-2 sqrt(7) - 8)/2

Factor 2 from -8 - 2 sqrt(7) giving 2 (-sqrt(7) - 4):
x = sqrt(7) - 4 or x = 1/22 (-sqrt(7) - 4)

(2 (-sqrt(7) - 4))/2 = -sqrt(7) - 4:

Answer: x = sqrt(7) - 4 or x = -sqrt(7) - 4_____________________________________________________

Solve for x:
x^2 + 8 x + 9 = 0

Subtract 9 from both sides:
x^2 + 8 x = -9

Add 16 to both sides:
x^2 + 8 x + 16 = 7

Write the left hand side as a square:
(x + 4)^2 = 7

Take the square root of both sides:
x + 4 = sqrt(7) or x + 4 = -sqrt(7)

Subtract 4 from both sides:
x = sqrt(7) - 4 or x + 4 = -sqrt(7)

Subtract 4 from both sides:
Answer:  x = sqrt(7) - 4 or x = -4 - sqrt(7)
4 0
3 years ago
Can someone tell me what x equals
Troyanec [42]
X=22. The supplementary angle is 90°, so the 66° angle, plus (x+2) has to add up to 90° too.
4 0
3 years ago
What are the names to these quadrilaterals ​
olga_2 [115]

Answer:

The top left one is a pentagon, the lower left is a quadrilateral, the top right is a rhombus, and the bottom left is a parallelogram.

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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