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olchik [2.2K]
2 years ago
14

(Will give brainliest help asap pls)

Mathematics
1 answer:
DanielleElmas [232]2 years ago
6 0
D because 5.50 is x and your y so boom D
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I’m being timed hurry!!!
umka21 [38]

Step-by-step explanation:

go left 10 and down 2 this due to the numbers being negative.

6 0
3 years ago
Read 2 more answers
Which equation is the inverse of 5 y + 4 = (x + 3) squared + one-half?
8_murik_8 [283]

The inverse of the given function is y = √5x + 7/2 - 3

<h3>Inverse of a function</h3>

Given the function expressed below;

5y + 4 = (x+3)² +1/2

5y = (x+3)² - 7/2

y = 1/5(x+3)² - 7/10

Replace y as x

x = 1/5(y+3)² - 7/10

Make y the subject of the formula

5x = (y+3)²- 7/2

(y+3)² = 5x + 7/2

y+3 = √5x + 7/2

y = √5x + 7/2 - 3

Hence the inverse of the given function is y = √5x + 7/2 - 3

learn more on inverse of a function here: brainly.com/question/3831584

#SPJ1

4 0
2 years ago
What is the perimeter of a polygon with verticals at (-1, 3) , (-1, 6) , (2, 10) , (5, 6) , and (5, 3)
Marat540 [252]

Answer:

22 units

Step-by-step explanation:

The perimeter of a polygon is said to be the sum of the length of it's sides.

From the question, we have 5 vertices. This means the polygon is a pentagon. It's given vertices are

A = (−1, 3)

B = (−1, 6) ​

C = (2, 10)

D = (5, 6) ​​

E = (5, 3) ​

To find the distance between two points, we use the formula

d = √[(y2 - y1)² + (x2 - x1)²]

Between A and B, we have

d(ab) = √[(6 - 3)² + (-1 --1)²]

d(ab) = √(3²) + 0

d(ab) = √9 = 3

Between B and C, we have

d(bc) = √[(10 - 6)² + (2 --1)²]

d(bc) = √[4² + 3²]

d(bc) = √(16 + 9) = √25 = 5

Between C and D, we have

d(cd) = √[(6 - 10)² + (5 - 2)²]

d(cd) = √[(-4)² + 3²]

d(cd) = √(16 + 9) = √25 = 5

Between D and E, we have

d(de) = √[(3 - 6)² + (5 - 5)²]

d(de) = √(-3)² + 0

d(de) = √9 = 3

Between E and A, we have

d(ea) = √[(3 - 3)² + (5 --1)²]

d(ea) = √[0 + (6)²]

d(ea) = √36 = 6

The perimeter is given as

d(ab) + d(bc) + d(cd) + d(de) + d(ea) =

3 + 5 + 5 + 3 + 6 = 22 units

7 0
3 years ago
16−2t= 3/2t+9<br> need help asap this is my grade plz <br> kahn academy<br> plz help meee
uranmaximum [27]

Answer:

t=2

Step-by-step explanation:

I worked it out and got this answer as well but checked it in a calculator and couldn't send my pic in. I hope its right but if t is with 2 on the denominator then its a whole different answer.

3 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
4 years ago
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