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3 years ago

Express the fractions 1/2, 3/16, and 7/8 with an LCD

1 answer:

5 0

<span>Least Common Denominator (LCD) is the least number which all the denominators can divide without remainder. The given denominators are 2, 16 and 8. The least number 2, 16 and 8 will divide without remainder is 16. Therefore, to express the fractions 1/2, 3/12, and 7/8 with an LCD, we multiply both the numerator and the denominator of each of the fractions with a common factor that makes the denominator to be 16. Therefore, 1/2, 3/16 and 7/8 expressed with an LCD are (1 x 8) / (2 x 8), 3/16, (7 x 2) / (8 x 2) = 8/16, 3/16, and 14/16.</span>

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What is the 17th term in the arithmetic sequence -1, -101, -201, -301...

OLEGan [10]

Answer:

I assume that the question is to prove that; a/(b + c), b/(c +a) and c/(a + b) are in an A.P

Step-by-step explanation:

It is given that a^2 , b^2 and c^2 are in an AP

So they have a common difference

b^2 - a^2 = c^2-b^2

(b - a)(b + a) = (c - b)(c + b)

(b - a) / (b + c) = (c - b) / (b + a)

Let;

(b - a) / (b + c) = (c - b) / (b + a) = K

Now for a/(b + c) , b/(c + a) and c/(a+ b)

b/(c+a) - a/(b+c)

= b(b+c) - a(a+c) / (b+c)(c+a)

= b^2 + bc - a^2 - ac / (b+c)(c+a)

= (b-a)(b+a) + c(b-a)

= (b-a)(b+a+c) / (b+c)(c+a)

= K(a+b+c) / (c+a)

c/(a+b) - b/(c+a)

= c^2 + ac - ab - b^2 /

= (c-b)(c+b) + a(c-b)

= (c - b)(a+b+c) / (a+b)(c+a)

= K(a+b+c) / (c+a)

So;

b/(c+a) - a/(b+c) = c/(a+b) - b/(c+a)

Which means that terms a/(b+c) , b/(c+a) and c/(a+b) have a a common difference

Therefore a/(b+c) , b/(c+a) and c/(a+b) are in an A.P

8 0

3 years ago

BRAINIEST AND 30 POINTS

Sergeu [11.5K]

Answer:

i think B. Midsegment of a Triangle Theorem is answer

8 0

2 years ago

What is the midpoint of the line segment with endpoints of (-2,-2) and (4,6)?

slamgirl [31]

Answer:

option (d) is correct.

The mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Step-by-step explanation:

Given: end points of a line segment as (-2,-2) and (4,6)

We have to find the mid points of the line segment whose ends points are given.

Mid point formula is stated as ,

For a line having end points as $\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right)$ , the mid point can be calculated as,

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

Here,

$\left(x_1,\:y_1\right)=\left(-2,\:-2\right),\:\left(x_2,\:y_2\right)=\left(4,\:6\right)$

Substitute in mid point formula, we get,

$=\left(\frac{4-2}{2},\:\frac{6-2}{2}\right)$

Solving further , we get,

$=\left(1,\:2\right)$

Thus, the mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Thus, option (d) is correct.

6 0

3 years ago

Read 2 more answers

Ron is slicing 5 pizzas each pizza slice is 1/8 of the pizza. How many pizza slices will be there in all

Goryan [66]

Answer:

there would be 40 slices of pizza

Step-by-step explanation:

If 5 pizzas each have 8 slices you multiply 5 X 8 which equals 40 slices

3 0

4 years ago

Read 2 more answers

How do you write 720,080 in expanded form with exponents

liraira [26]

The expanded form for that problem would be (7x10^5) + (2 × 10^4) + (8x10^1)
when i put ^then a number i mean to that power like 2 to the 4th power i would write 2^4

8 0

3 years ago