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3 years ago

X=4y+2 in slope intercept form

Mathematics

2 answers:

Leto [7]3 years ago

7 0

X=4y+2 move terms
-4y=2-x change the signs
4y=-2+x divid both sides by 4
y=-1/2+1/4x reorder terms

y= 1/4x-1/2

siniylev [52]3 years ago

5 0

Answer:
The slope intercept form is y=mx+c
So,
x=4y+2 should also be made in that form
x-2=4y
y=(x-2)/4
That’s the final answer in slope intercept form

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solmaris [256]

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3 years ago

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The red blood cell counts (in millions of cells per microliter) for a population of adult males can be approximated by a norma

skad [1K]

Answer:

(a) Minimum red blood cells 5.744 million cells per micro liter

(b) Maximum red blood cells 5.068 million cells per micro liter.

Step-by-step explanation:

Z-score formula is = $\frac{x-u}{Standard deviation}$

Z-score = $\frac{x-5.5}{0.4}$

The value of z-score is 0.61 so then x will be;

x = 5.744

The minimum red blood cells count that can in top is 27% of count which is 5.744 million cells per micro liter.

Z-score = $\frac{x-5.5}{0.4}$

The value of z-score is 0.14 so then x will be;

x = 5.068

The maximum red blood cells count that can be in top is 14% of count which is 5.068 million cells per micro liter.

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3 years ago

Use braces and digits to indicate the set of whole numbers

Sergeeva-Olga [200]

Whole numbers are numbers without decimal points greater than 0.

The set of whole numbers is:

$W =\{0,1,2,3,4.....\}$

In the introductory part of this solution, I stated that:

Whole numbers do not have decimal point
The smallest whole number is 0

This means that the following numbers are whole numbers:

1, 9, 10, 67

While the following numbers are not:

-1, 9.0, 1.0, -67

Let W be the set of whole numbers; the set is:

$W =\{0,1,2,3,4.....\}$

The dots after 4 means the set still continues

Read more at:

brainly.com/question/13106807

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2 years ago

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sergejj [24]

Step-by-step explanation:

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Cint%20t%5E2%2B1%20%5C%20dt" id="TexFormula1" title="\frac{d}{dx} \

Kisachek [45]

Answer:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} \ = \ 2x^5-8x^2+2x-2$

Step-by-step explanation:

$\displaystyle{\frac{d}{dx} \int \limits_{2x}^{x^2} t^2+1 \ \text{dt} = \ ?$

We can use Part I of the Fundamental Theorem of Calculus:

$\displaystyle\frac{d}{dx} \int\limits^x_a \text{f(t) dt = f(x)}$

Since we have two functions as the limits of integration, we can use one of the properties of integrals; the additivity rule.

The Additivity Rule for Integrals states that:

$\displaystyle\int\limits^b_a \text{f(t) dt} + \int\limits^c_b \text{f(t) dt} = \int\limits^c_a \text{f(t) dt}$

We can use this backward and break the integral into two parts. We can use any number for "b", but I will use 0 since it tends to make calculations simpler.

$\displaystyle \frac{d}{dx} \int\limits^0_{2x} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

We want the variable to be the top limit of integration, so we can use the Order of Integration Rule to rewrite this.

The Order of Integration Rule states that:

$\displaystyle\int\limits^b_a \text{f(t) dt}\ = -\int\limits^a_b \text{f(t) dt}$

We can use this rule to our advantage by flipping the limits of integration on the first integral and adding a negative sign.

$\displaystyle \frac{d}{dx} -\int\limits^{2x}_{0} t^2+1 \text{ dt} \ + \ \frac{d}{dx} \int\limits^{x^2}_0 t^2+1 \text{ dt}$

Now we can take the derivative of the integrals by using the Fundamental Theorem of Calculus.

When taking the derivative of an integral, we can follow this notation:

$\displaystyle \frac{d}{dx} \int\limits^u_a \text{f(t) dt} = \text{f(u)} \cdot \frac{d}{dx} [u]$
where u represents any function other than a variable

For the first term, replace $\text{t}$ with $2x$ , and apply the chain rule to the function. Do the same for the second term; replace

$\displaystyle-[(2x)^2+1] \cdot (2) \ + \ [(x^2)^2 + 1] \cdot (2x)$

Simplify the expression by distributing $2$ and $2x$ inside their respective parentheses.

$[-(8x^2 +2)] + (2x^5 + 2x)$
$-8x^2 -2 + 2x^5 + 2x$

Rearrange the terms to be in order from the highest degree to the lowest degree.

$\displaystyle2x^5-8x^2+2x-2$

This is the derivative of the given integral, and thus the solution to the problem.

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2 years ago