Answer:
500 together and they are all the same
Step-by-step explanation:
To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
![52 \sqrt[5]{7}](https://tex.z-dn.net/?f=52%20%5Csqrt%5B5%5D%7B7%7D%20)
Step-by-step explanation:
![= 52 \sqrt[5]{7}](https://tex.z-dn.net/?f=%20%3D%2052%20%5Csqrt%5B5%5D%7B7%7D%20)
Im not too sure with these, but this is what i got
11. 39.90
12.16
13.182.8
14.220
15.499
16.19.5
