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2 years ago

Solve 3x-2/4 - 2x+5/3 = 1-x/6

Mathematics

1 answer:

Nadya [2.5K]2 years ago

7 0

Answer:

Pasos para resolver una ecuación lineal

3x−2/4−2x+5/3=1−x/6

Multiplique ambos lados de la ecuación por 12, el mínimo común denominador de 4,3,6.

36x−3×2−24x+20=12−2x

Multiplica −3 y 2 para obtener −6.

36x−6−24x+20=12−2x

Combina 36x y −24x para obtener 12x.

12x−6+20=12−2x

Suma −6 y 20 para obtener 14.

12x+14=12−2x

Agrega 2x a ambos lados.

12x+14+2x=12

Combina 12x y 2x para obtener 14x.

14x+14=12

Resta 14 en los dos lados.

14x=12−14

Resta 14 de 12 para obtener −2.

14x=−2

Divide los dos lados por 14.

−2

Reduzca la fracción

−2

a su mínima expresión extrayendo y anulando 2.

x=−

Step-by-step explanation:

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7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$