So it is asking you to group like term so
x terms can be grouped/added/subtracted to other x terms, but not to x^2 or x^3 terms
x^2 terms to x^2 and so on so
1. 9-3k+5k=
9+(5k-3k)=
9+2k
2. k^2+2k+4k=
k^2+(2k+4k)=
k^2+6k=
Quadrant Four (IV) since the x coordinate is a positive and the y coordinate is a negative.
Answer:
![\sqrt[3]{9}= 2.08008...](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B9%7D%3D%202.08008...)
Step-by-step explanation:
I used a calculator but 9 is not a perfect cube
Answer:
I think it's C) 18.5ft^2
it's just an educated guess though I haven't worked on area in a while
Answer:
<u><em>y = 63</em></u>
Step-by-step explanation:
<em>y is directly proportional to x²</em>
<em>As given,</em>
<em>when y = 3 => x = 2</em>
<em>So, 3 = 4 - 1</em>
<em>Which means the relation can be written as :-</em>
<em>y = x² - 1</em>
<em></em>
<em>Substituting x = 8</em>
<em>y = (8)² - 1</em>
<em>y = 64 - 1</em>
<u><em>y = 63</em></u>
