Answer:
Step-by-step explanation:
<u>Solve the given for h:</u>
<u>Isolate h:</u>
<u>Divide all terms by 2πr:</u>
Correct choice is A
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
1:4
Step-by-step explanation:
Answer:
Answer is in the attachment.
Step-by-step explanation:
To graph x>2 consider first x=2. x=2 is a vertical line and if you want to graph x>2 you need to shade to the right of the vertical line.
To graph x+y<2, I will solve for y first.
x+y<2
Subtract x on both sides:
y<-x+2
Consider the equation y=-x+2. This is an equation with y-intercept 2 and slope -1 or -1/1. So the line you have in that picture looks good for y=-x+2. Now going back to consider y<-x+2 means we want to shade below the line because we had y<.
Now where you see both shadings will be intersection of the shadings and will actually by your answer to system of inequalities you have. In my picture it is where you have both blue and pink.
I have a graph in the picture that shows the solution.
Also both of your lines will be solid because your question in the picture shows they both have equal signs along with those inequality signs.
Just in case my one graph was confusing, I put a second attachment with just the solution to the system.
Answer:
34.5 ft
Step-by-step explanation:
~Refer to the attachment for the solution.