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jekas [21]
3 years ago
9

What's the rule for 830 823 817 812 808​

Mathematics
1 answer:
yanalaym [24]3 years ago
7 0

Answer:

Each time you subtract one less then before

Step-by-step explanation:

I know this because from 830 to 823 they subtracted by 7 and then from 823 to 817 they subtracted by 6 so it keep going down the line.

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Wires manufactured for use in a computer system are specified to have resistances between 0.11 and 0.13 ohms. The actual measure
Marina CMI [18]

Answer:

a) P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

b) P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the resitances of a population, and for this case we know the distribution for X is given by:

X \sim N(0.12,0.009)  

Where \mu=0.12 and \sigma=0.009

We are interested on this probability

P(0.11

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(0.11

And we can find this probability with this difference and with the normal standard table or excel:

P(-1.11

Part b

We select a sample size of n =4. And since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want this probability:

P(0.11 < \bar X < 0.13)

And we can use the z score defined by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using the limits we got:

z = \frac{0.11-0.12}{\frac{0.009}{\sqrt{4}}}= -2.22

z = \frac{0.13-0.12}{\frac{0.009}{\sqrt{4}}}= 2.22

And we want to find this probability:

P(-2.22< Z

4 0
3 years ago
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An 8-sided die is rolled. Find the probability of rolling a 1 or even number
leonid [27]

The probability of rolling a 1 or an even number is 5/8.

If there are 8 sides of the die from numbers 1-8, the numbers of the probability are 1, 2, 4, 6, and 8. That makes 5 numbers out of 8 possible numbers. So, the probability is 5/8.(62.5%)

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In a study, a group of 10-year-old boys are fed doughnuts every morning for a week and then weighed to see how much weight they
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The amount of weight gained
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What is 447 times 63.
kiruha [24]
447 times 63 is 28,161. 
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Determine the missing factor
kogti [31]

Answer:

2x-1

Step-by-step explanation:

Just solve this way.

(2/3)x-(1/3)=(1/3)y.

Now find y in terms of x.

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2 years ago
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