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vladimir1956 [14]
2 years ago
12

Find the 6th term of the arithmetic sequence X – 9, -X – 11, -3.3 – 13, ...

Mathematics
1 answer:
MrMuchimi2 years ago
3 0

Answer:

-13x-23

Step-by-step explanation:

Given sequence:  x-9, -x-11, -3x-13

Therefore,

  • a_1=x-9
  • a_2=-x-11
  • a_3=-3x-13

General form of an arithmetic sequence: a_n=a+(n-1)d

(where a is the first term and d is the common difference)

To find the common difference, subtract a term from the next term:

\begin{aligned}d & =a_2-a_1\\ & =(-x-11)-(x-9)\\ & = -x-11-x+9\\ & = -2x-2\end{aligned}

Therefore,

a_n & =(x-9)+(n-1)(-2x-2)

To find the 6th term, input n = 6 into the equation:

\begin{aligned}\implies a_6 & =(x-9)+(6-1)(-2x-2)\\ & = (x-9)+7(-2x-2)\\ & = x-9-14x-14\\ & = -13x-23\end{aligned}

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Now 2 and 3 are same since in both the cases we need to square 2 only not the negative 1 in it

1 is not same to 2 and 3 since in 1 we need to square 2 and negative 1 in it also.

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