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4 years ago

15

0.2(x+50)-6=0.4(3x+20) ( show work please)

2 answers:

garri49 [273]4 years ago

7 0

Let's solve your equation step-by-step.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span>Step 1: Simplify both sides of the equation.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span><span><span><span><span><span><span>(0.2)</span><span>(x)</span></span>+<span><span>(0.2)</span><span>(50)</span></span></span>+</span>−6</span>=<span><span><span>(0.4)</span><span>(<span>3x</span>)</span></span>+<span><span>(0.4)</span><span>(20)</span></span></span></span>(Distribute)<span><span><span><span><span>0.2x</span>+10</span>+</span>−6</span>=<span><span>1.2x</span>+8</span></span><span><span><span>(<span>0.2x</span>)</span>+<span>(<span>10+<span>−6</span></span>)</span></span>=<span><span>1.2x</span>+8</span></span>(Combine Like Terms)<span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span><span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span>Step 2: Subtract 1.2x from both sides.<span><span><span><span>0.2x</span>+4</span>−<span>1.2x</span></span>=<span><span><span>1.2x</span>+8</span>−<span>1.2x</span></span></span><span><span><span>−<span>1x</span></span>+4</span>=8</span>Step 3: Subtract 4 from both sides.<span><span><span><span>−<span>1x</span></span>+4</span>−4</span>=<span>8−4</span></span><span><span>−<span>1x</span></span>=4</span>Step 4: Divide both sides by -1.<span><span><span>−<span>1x</span></span><span>−1</span></span>=<span>4<span>−1</span></span></span><span>x=<span>−4</span></span>Answer:<span>x=<span>−<span>4</span></span></span>

erik [133]4 years ago

4 0

X = -4 can't show the work sorry:(

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Step-by-step explanation:

When there are a number of overlapping shaded areas on the graph, I find it convenient to use the reverse of the inequalities. That makes the <em>unshaded</em> area the solution space. Here, the vertices of the triangular solution space are ...

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