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2 years ago

Solve the following formula for

Mathematics

1 answer:

Svetllana [295]2 years ago

6 0

Question is not stated clearly

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rjkz [21]

Answer:

95°

Step-by-step explanation:

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2 years ago

Determine whether the graph represents a proportional relationship.

Dafna1 [17]

Answer:

Step-by-step explanation:

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3 years ago

CEREAL of the 35 types of cereal sold in a store, 15are advertised to be whole grain. What fraction, in simplest form, of the ce

Vesnalui [34]

Answer:

The answer is 3/7

Step-by-step explanation:

Find the GCD of both 35 and 15. This is 5.

Then, divide the numerator and denominator by the GCD.

15 ÷ 5/ 35 ÷ 5

This equals 3/7.

6 0

2 years ago

Complete parts a through c for the given function.

victus00 [196]

Answer:

a. The critcal points are at

$x=0,-5,3$

b. Then, $x = -5$ is a maximum and $x=3$ is a minimum

c. The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

Step-by-step explanation:

(a)

Remember that you need to find the points where

$f'(x)=0$

Therefore you have to solve this equation.

$20x^4 + 40x^3 - 300x^2 = 0$

From that equation you can factor out $20x^2$ and you would get

$20x^2 ( x^2 +2x - 15) = 0$

And from that you would have $20x^2 = 0$ , so $x = 0$ .

And you would also have $x^2 +2x-15 = 0$ .

You can factor that equation as $x^2 +2x -15 = (x+5)(x-3) = 0$

Therefore $x=-5 , x=3$ .

So the critcal points are at

$x=0,-5,3$

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

$f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\$

Then, $x = -5$ is a maximum and $x=3$ is a minimum

The absolute minimum is at $x = 3$ and the absolute maximum is at $x = -5.$

6 0

2 years ago

Read 2 more answers

I ONLY HAVE UNTIL 12PM TODAY

Reil [10]

where's the question

5 0

3 years ago