Could someone help me plz???

Jocelyn just accepted a job at a new company where she will make an annual salary of $70000. Jocelyn was told that for each year

Oksanka [162]

Answer:

$80,500

55,500 + 1,500t

Step-by-step explanation:

The question is an arithmetic progression series

Where,

a= first term

d= common difference

n= number of terms

a = $70,000

d= $1,500

n= 8 years

8th term = a + (n-1) d

= 70,000 + (8-1)1500

= 70,000 + 7(1500)

= 70,000 + 10,500

= $80,500

Jocelyn salary after 8 years is $80,500

Solve for when n = t

t th term = a + (n-1)d

= 70,000 + (t - 1)1500

= 70,000 + 1,500t - 1,500

= 55,500 + 1,500t

t th term = 55,500 + 1,500t

4 0

3 years ago

Simplify this equation, also what is the sign beside 150 and what does it do

Solnce55 [7]

Answer:

<h2>hope it helps you see the attachment for further information ✌✌✌✌✌</h2>

6 0

3 years ago

A realtor would like to create a 95% confidence interval for the average price of a house in Franklin County, Ohio. To accomplis

VMariaS [17]

Answer:

$320128-1.96\frac{50324}{\sqrt{529}}=315839.52$

$320128+1.96\frac{50324}{\sqrt{529}}=324416.48$

So on this case the 95% confidence interval would be given by (315839.52;324416.48)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=320128$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=50324$ represent the population standard deviation

n=529 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$320128-1.96\frac{50324}{\sqrt{529}}=315839.52$

$320128+1.96\frac{50324}{\sqrt{529}}=324416.48$

So on this case the 95% confidence interval would be given by (315839.52;324416.48)

8 0

3 years ago

How do you solve the problem 6-3x=-2x

jolli1 [7]

6-3x=2x

In order to solve these, you first want to get all the variables on one side. So, you add 3x to both sides.

6=x

The answer is x=6

Hope this helps!

3 0

3 years ago

Read 2 more answers

Apply the distributive property to factor out the greatest common factor. 12+20

vladimir2022 [97]

Answer:

4 is the answer.

Step-by-step explanation:

Braunliest?

6 0

3 years ago