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xxMikexx [17]
3 years ago
9

10m^2n+30mn^2+5mn factor the polynomial

Mathematics
2 answers:
Softa [21]3 years ago
5 0
  • 5mn(2m+6n + 1)

\:

Explanation :

So, here we are to factor the polynomial :

\\ \longrightarrow \sf \qquad10m^2n+30mn^2+5mn\\ \\

\longrightarrow \sf \qquad5mn(2m+6n + 1)\\ \\

Some points to know :

  • Factorisation is the reverse process of multiplucation.

  • The Factorisation is the process of finding two or more expressions such that their product is the given expression
Vedmedyk [2.9K]3 years ago
5 0

Answer:

\boxed{5\left(6mn^{2}+mn+2\left(m^{n}\right)^{2}\right)}

Step-by-step explanation:

10m  ^ { 2n  }  +30mn  ^ { 2  }  +5mn

Factor out the common factor: 5

=5\left(2m^{2n}+6mn^{2}+mn\right)

=5\left(6mn^{2}+mn+2\left(m^{n}\right)^{2}\right)

=》This expression cannot be further simplified.

___________

Hope it helps ⚜

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3 years ago
A shipment of 18 televisions sets contains 3 defective sets. A hotel purchases 8 of these televisions sets. What is the probabil
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Answer:

85.29%

Step-by-step explanation:

We know 18 televisions sets contains 3 defective sets => 15 TV sets are ok

So the total number of possible ways for the hotel to buy = C^{18} _{8} = 43758

At least one of the defective sets, so we need to find the probability for 1 defective sets, 2 defective sets and 3 defective sets.

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P(1) = C^{15} _{7} * C^{3} _{1} = 6435*3 = 19305

2.  The number of ways  the hotel purchases 8 of these televisions sets but have 2 defective one:

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6 0
3 years ago
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