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lapo4ka [179]
2 years ago
11

Which of the following best represents the graph of the line with the equation 5x – 2y = 10?

Mathematics
1 answer:
IRISSAK [1]2 years ago
5 0
The answer for this is d because it has a rise of 5 and run of 2
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10 bags needed .......

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The graph of f(t) = 3.2 shows the value of a rare coin in year t. What is the
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B. Every year the coin is worth 3 more dollars.

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Can 3.65909090909 be expressed as a fraction whose denominator is a power of 10? Explain.
GuDViN [60]
\bf 3.659\textit{ can also be written as }\cfrac{3659}{1000}\textit{ therefore }3.6590909\overline{09}\\\\
\textit{can be written as }\cfrac{3659.0909\overline{09}}{1000}

notice above, all we did, was isolate the "recurring part" to the right of the decimal point, so the repeating 09, ended up on the right of it.

now, let's say, "x" is a variable whose value is the recurring part, therefore then

\bf \cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \qquad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}

now, the idea behind the recurring part is that, we then, once we have it all to the right of the dot, we multiply it by some power of 10, so that it moves it "once" to the left of it, well, the recurring part is 09, is two digits, so let's multiply it by 100 then, 

\bf \begin{array}{llllllll}
100x&=&09.0909\overline{09}\\
&&9+0.0909\overline{09}\\
&&9+x
\end{array}\quad \implies 100x=9+x\implies 99x=9
\\\\\\
x=\cfrac{9}{99}\implies \boxed{x=\cfrac{1}{11}}\\\\
-------------------------------\\\\
\cfrac{3659.0909\overline{09}}{1000}\qquad \boxed{x=0.0909\overline{09}} \quad \cfrac{3659+0.0909\overline{09}}{1000}\implies \cfrac{3659+x}{1000}
\\\\\\
\cfrac{3659+\frac{1}{11}}{1000}

and you can check that in your calculator.
8 0
4 years ago
Which of the following is the complete factorization of 3x2-6x-240?
AURORKA [14]
1.  Reduce  <span>3x2-6x-240   to    x^2 - 2x - 80

2.  Use " ^ " to indicate exponentiation

3.  Factor  </span>x^2 - 2x - 80 using completing the square:

     x^2 - 2x + 1^2 - 1^2 - 80

         (x+1)^2 - 1  - 80
          (x+1)^2 - 81
          (x+1)^2 - 9^2  = (x+1-9)(x+1 +9), or (x-8)(x+10)

Final answer, with all factors shown:      3(x-8)(x+10)
4 0
3 years ago
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