Juno boots 57 oranges in bags each bag holds 6 oranges use the area 2 divided

The design for the palladium window shown includes a semicircular shape at the top. The bottom is formed by squares of equal siz

9966 [12]

Answer:

$(a)\ Area = 3765.32$

$(b)\ Area = 4773$

Step-by-step explanation:

Given

$A_1 = 169in^2$ --- area of each square

$Shade = 4in$

See attachment for window

Solving (a): Area of the window

First, we calculate the dimension of each square

Let the length be L;

So:

$L^2 = A_1$

$L^2 = 169$

$L = \sqrt{169$

$L=13$

The length of two squares make up the radius of the semicircle.

So:

$r = 2 * L$

$r = 2*13$

$r = 26$

The window is made up of a larger square and a semi-circle

Next, calculate the area of the larger square.

16 small squares made up the larger square.

So, the area is:

$A_2 = 16 * 169$

$A_2 = 2704$

The area of the semicircle is:

$A_3 = \frac{\pi r^2}{2}$

$A_3 = \frac{3.14 * 26^2}{2}$

$A_3 = 1061.32$

So, the area of the window is:

$Area = A_2 + A_3$

$Area = 2704 + 1061.32$

$Area = 3765.32$

Solving (b): Area of the shade

The shade extends 4 inches beyond the window.

This means that;

The bottom length is now; Initial length + 8

And the height is: Initial height + 4

In (a), the length of each square is calculated as: 13in

4 squares make up the length and the height.

So, the new dimension is:

$Length = 4 * 13 + 8$

$Length = 60$

$Height = 4*13 + 4$

$Height = 56$

The area is:

$A_1 = 60 * 56 = 3360$

The radius of the semicircle becomes initial radius + 4

$r = 26 + 4 = 30$

The area is:

$A_2 = \frac{3.14 * 30^2}{2} = 1413$

The area of the shade is:

$Area = A_1 + A_2$

$Area = 3360 + 1413$

$Area = 4773$

7 0

2 years ago

I need help with this...

lisov135 [29]

ln 5
e = ?
x
Keep in mind that y=e and y = ln x are inverse functions of one another.
ln 5
e , we can drop both the "e" and the "ln 5." We are left with 5 (answer).
ln 5
Alternatively, we could take the ln of both sides of y = e

which will result in ln y = (ln 5) ln e. Note that ln e = 1 (these two functions are inverses of one another).

Then we are left with ln y = ln 5. Dropping the "ln" operator from both sides,

y=5 (same as before).

8 0

3 years ago

Which function represents g(x), a reflection of f(x) = 4

mel-nik [20]

Answer: Correct answer is C -I just took the test

we have the function f(x) = 4(1/2)x, and we want to reflex it over the x-axis.

you can see in the graph that the reflex over this axis changes the sign of f(x) in all the points (where f(0) = 4, g(0) = -4, f(1) = 2, g(1) = -2, and so on), then the reflex, g(x) is equal to -f(x)

now we have:

g(x) = -f(x) = - 4(1/2)x

then the right answer is the third option:

g(x) = -4(1/2)x

Step-by-step explanation:

7 0

3 years ago

Marie is getting married tomorrow, at an outdoor ceremony in the desert. In recent years, it has rained only 5 days each year. U

kogti [31]

Answer:

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Forecast of rain.

Event B: Raining.

In recent years, it has rained only 5 days each year.

A year has 365 days. So

$P(B) = \frac{5}{365} = 0.0137$

When it actually rains, the weatherman correctly forecasts rain 90% of the time.

This means that $P(A|B) = 0.9$

Probability of forecast of rain:

90% of 0.0137(forecast and rains)

10% of 1 - 0.0137 = 0.9863(forecast, but does not rain)

$P(A) = 0.0137*0.9 + 0.9863*0.1 = 0.11096$

What is the probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

$P(B|A) = \frac{0.0137*0.9}{0.11096} = 0.1111$

11.11% probability that it will rain on the day of Marie's wedding, given the weatherman forecasts rain

3 0

2 years ago

Two parallel lines are crossed by a transversal

Olegator [25]

B. H=60
180degrees-120degrees=60degrees

8 0

2 years ago

Juno boots 57 oranges in bags each bag holds 6 oranges use the area 2 divided​

Juno boots 57 oranges in bags each bag holds 6 oranges use the area 2 divided