90 over 7 EndFraction divided by 1 and three-fourths

Mathematics

1 answer:

saul85 [17]2 years ago

7 0

Answer:

7 $\frac{17}{49}$

Step-by-step explanation:

$\frac{90}{7}$ ÷1 $\frac{3}{4}$

= $\frac{90}{7}$ × $\frac{7}{3}$ ( keep change flip )

= $\frac{360}{49}$

=7 $\frac{17}{49}$

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Find f(x)=x^2-x^3,find f(-10)

sergij07 [2.7K]

Answer:

f(-10) = 1,100

Step-by-step explanation:

f(-10) = (-10)^2 - (-10)^3

= 100 - (-1000)

= 1,100

3 0

3 years ago

Isabella's rain gauge showed 3 centimeters/cra) last Tuesday. This Tuesday,

Llana [10]

<h3><u>Question:</u></h3>

Isabella’s rain gauge showed 3 4/5 centimeters (cm) last Tuesday. This Tuesday, the rain gauge showed 5 7/10 centimeters. How many more centimeters of rain fell during the week?

A 9 1/2cm B 8 1/2cm c 2 4/5cm D 1 9/10 cm

<h3><u>Answer:</u></h3>

Option D

$1\frac{9}{10}$ more centimeters of rain fell during this week than last week

<h3><u>Solution:</u></h3>

From given,

$Last\ tuesday = 3\frac{4}{5}\ cm\\\\Convert\ to\ improper\ fraction\\\\Last\ tuesday = \frac{5 \times 3 + 4}{5} = \frac{19}{5}\ cm$

Also given that,

$This\ tuesday = 5\frac{7}{10}\ cm = \frac{10 \times 5 + 7}{10} = \frac{57}{10}\ cm$

<em><u>How many more centimeters of rain fell during the week?</u></em>

$This\ tuesday - last\ tuesday = \frac{57}{10} - \frac{19}{5}\\\\This\ tuesday - last\ tuesday = \frac{57}{10} - \frac{19 \times 2}{5 \times 2}\\\\This\ tuesday - last\ tuesday = \frac{57-38}{10}\\\\This\ tuesday - last\ tuesday = \frac{19}{10}\\\\Converting\ to\ mixed\ fraction\\\\\rightarrow \frac{19}{10} = 1\frac{9}{10}$