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Lady bird [3.3K]
3 years ago
15

Daphne has a preloaded games card that she is using to play games at the arcade as shown in the table.

Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
6 0

Answer:

she starts with $25

every three games she spends $1.50 (.50 per game)

Step-by-step explanation:

i mean i cant really explain it, its kinda self explanatory

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Which statement or statements accurately describe a good way to avoid excessive service fees? I. Try to deposit money in large b
Phantasy [73]

Answer:

Option B: II only

Step-by-step explanation:

Looking at the statements;

In statement I, whether making big at once or small deposits periodically, they have no impact in terms of charges from banks because banks don't charge any excessive fee for direct deposits.

In statement II, using out of network ATM would mean more excessive service fees. This is because your host bank which issued you the ATM card will charge you for using a non - network machine. In addition to that, the ATM operator where you are withdrawing from will also charge you a fee. This is double charge from 2 streams thus avoiding it will mean no excessive charges.

In statement III, some banks may or may not issue some fee for making online transactions with debit card depending on what exactly you want to do. However, it's just a small fee and thus, using it doesn't cause excessive charges.

Thus, the one to avoid will be statement II.

5 0
3 years ago
Given that y is directly proportional to x. If y = 30 and x= 5, write an equation that connects y with x.
Licemer1 [7]

Given:

y is directly proportional to x.

y=30 when x=5

To find:

The equation that connects y with x.

Solution:

It is given that, y is directly proportional to x. So,

y\propto x

y=kx                     ...(i)

Where, k is the constant of proportionality.

We have, y=30 when x=5. Substituting these values in (i), we get

30=k(5)

Divide both sides by 5.

\dfrac{30}{5}=k

6=k

Substituting k=6 in (i), we get

y=6x  

Therefore, the required equation is y=6x.

8 0
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gavmur [86]

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