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Vikki [24]
2 years ago
10

I need help PLEASEEEEEEEEEEEEEE

Mathematics
2 answers:
Serjik [45]2 years ago
5 0

Answer:

318

Step-by-step explanation:

A=2(wl+hl+hw)=2·(9·3+11·3+11·9)=318

cupoosta [38]2 years ago
4 0

Answer:

318

Step-by-step explanation:

318 is the required answer

I hope it helped you

So given Figure we need to find total surface area

=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)

=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)

From figure,

AB=DC=PQ=SR=9 cm

BQ=CR=AP=DS=11 cm

BC=AD=QR=SP=3 cm

On substituting these values We get

Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)

=27+33+27+33+99+99=318

I hope it helped you

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A circle with a radius of 5 cm has an area of 25π cm2. Which is the best approximation for the area of one-half of this circle?
kotegsom [21]

Answer:

A

Step-by-step explanation:

π=3.14159...

Full circle are 25π cm² = 25*3.14=78.5 cm²

Half 78.5 cm²/2 = 39.25 cm²

4 0
3 years ago
USE MY BINGO CLASH CODE TO EARN EXTRA DIGS!! WIN REAL MONEY WITH BINGO CLASH!!
alexdok [17]

Answer:

ok i guess...

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
At a certain university, the average attendance at basketball games has been 3125. Due to the dismal showing of the team this ye
Neporo4naja [7]

Answer:

The test statistic needed to evaluate the claim is t = -1.08.

Step-by-step explanation:

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value of the mean, s is the standard deviation of the sample and n is the size of the sample.

At a certain university, the average attendance at basketball games has been 3125. The athletic director claims that the attendance is the same as last year.

This means that \mu = 3125

Due to the dismal showing of the team this year, the attendance for the first 9 games has averaged only 2915 with a standard deviation of 585.

This means that n = 9, X = 2915, s = 585

What is the test statistic needed to evaluate the claim?

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{2915 - 3125}{\frac{585}{\sqrt{9}}}

t = -1.08

The test statistic needed to evaluate the claim is t = -1.08.

6 0
2 years ago
PLEASE PLEASE HELP I WILL MARK THE BRAINLIEST!!!!!
Free_Kalibri [48]

Answer:

<u>The average cost of a cat's annual visit is about <em>$23.71 less</em> at A New Leash on Life Animal Clinic than the average cost for a cat's annual visit at No Ruff Stuff Animal </u><u>Hospital.</u>

Explanation:

As you can see from the data and graph given, the Mean is essentially the average cost and $101.13 (New Leash on Life) is $23.71 less than $121.84 (No Ruff Stuff Animal Hospital).

8 0
3 years ago
A store sold 70 hammers and ranchers Hammer sold for $10 each in French so for five dollars each a total of 600.00 what's the co
MrMuchimi

Answer:

50 hammers and 20 wrenches.

Step-by-step explanation:

Let x represent number of hammers and y represent number of ranchers.

We have been given that a store sold 70 hammers and ranchers. We can represent this information in an equation as:

x+y=70...(1)

We are also told that each hammer sold for $10 and each rancher sold for five dollars resulting a total of 600.00. We can represent this information in an equation as:

10x+5y=600...(2)

From equation (1), we will get:

x=70-y

Substituting this value in equation (2), we will get:

700-10y+5y=600

700-5y=600

700-700-5y=600-700

-5y=-100

\frac{-5y}{-5}=\frac{-100}{-5}

y=20

Therefore, 20 wrenches were sold.

Now, we will substitute y=20 in equation (1) as:

x+20=70

x+20-20=70-20

x=50

Therefore, 50 hammers were sold.

5 0
3 years ago
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