All categories

1 year ago

What is the solution to 34x+95=3(14x +9)

Mathematics

1 answer:

True [87]1 year ago

3 0

Answer: x=8.5
34x+95=3(14x+9)
34x+95=42x+27
-34x -34x
————————-
95=8x+27
-27. -27
————————-
68=8x
68/8=8x/8
8.5=x

You might be interested in

Hhhheeeeeellllpppppppp

vovikov84 [41]

Ask me your other questions.i hope it was helpful

6 0

2 years ago

Write or draw to explain how you will find the total value of $1 bills and 3 quarters.

Rzqust [24]

"if you break down a $1 bill, it is 4 quarters. If you add the 4 quarters to the other 3 then you will get the sum of 7."

Hope this helps!

5 0

2 years ago

A polygon that undergoes a series of transformations that the image has the corresponding sides and angles of equal measure to t

Gnoma [55]

What did the answer end up being?

7 0

2 years ago

I need help with this

12345 [234]

Are you solving for x and y? 5y + 2(6x) would just be 5y + 12x

6 0

2 years ago

Suppose that a function f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence

Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

If there is vertical asymptote at x=c , then limit does not exist

Examples:

case-1:

$\lim_{x \to c} \frac{x^2-cx}{(x-c)}$

We can simplify it

$\lim_{x \to c} \frac{x(x-c)}{(x-c)}$

$=\lim_{x \to c} x$

$=c$

so, we can see that limit exist and it's value defined

case-2:

$\lim_{x \to c} \frac{1}{(x-c)}$

Left limit is

$\lim_{x \to c-} \frac{1}{(x-c)}$

$=-\infty$

Right Limit is

$\lim_{x \to c+} \frac{1}{(x-c)}$

$=+\infty$

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0

2 years ago