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viktelen [127]
2 years ago
15

Jim picks a five digit odd number. The second digit is less than 5. The fourth digit is a cube number. The first digit is a prim

e number. How many different numbers could he pick?
Mathematics
1 answer:
Nesterboy [21]2 years ago
5 0

Answer:

3,000 numbers.

Step-by-step explanation:

First digit: 2, 3, 5, or 7 (primes)

Second digit: 0, 1, 2, 3, or 4 (less than 5)

Third digit: 0-9

Fourth digit: 0, 1, or 8 (cubic numbers)

Fifth digit: 1, 3, 5, 7, or 9 (odd numbers)

So we have 4 * 5 * 10 * 3 * 5 = 3,000 possible numbers.

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Which ordered pair is a solution to the system of linear equations -4x+y= 8 and X-5y=17?
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3 years ago
4) When Php 20.247 is rounded to the nearest hundredths, it becomes A, Php 20.24 B. Php 20.25 C. Php 20.247 D. Php 20.248​
gayaneshka [121]

When Php 20.247 is rounded to the nearest hundredths, the value that will be gotten is Php. 20.25.

It should be noted that the 2 after the decimal is the tenth place, 4 is in the hundredth place and 7 is in the thousandth place.

Therefore, when Php 20.247 is rounded to the nearest hundredths, we'll add 1 to 4 since the thousandths place is above 5. Therefore, the new number is Php. 20.25.

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Consider the equation 2(x + 2) = 2 + 2x. How many solutions does it have?
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