Find the quotient: a 3 ft 4 in b 3 ft 9 in c 4 ft d 3 ft 8 in

How do you complete a tree map withe the following words estimation,benchmark,hundredth ,place value,round,tenth, thousandth

Mashcka [7]

I think you can put bench mark place valie round tenth thousnadth

3 0

3 years ago

Density of a 8200 gram brick that is 4 inches x 4 inches x 4 inches?

Tanzania [10]

Density = mass / volume
Density = 8,200 grams / (4*4*4)
Density = 8,200 grams / 64 cubic inches
Density = 128.125 grams / cubic inch

3 0

3 years ago

aalyn [17]

Answer:

Step-by-step explanation:

Using normal distribution,

z = (x - μ)/σ

μ= mean = 44 and

σ = standard deviation= 5.0

a) The probability that yield strength is at most 40=

P( x lesser than or equal to 40)

z = (40-44)/5= -0.8

Looking at the normal distribution table,

P( x lesser than or equal to 40) =0.2119

b) P(x greater than 62) = 1 - P(x lesser than or equal to 62)

z = (62-44)/5= 3.6

Looking at the normal distribution table,

P(x greater than 62) = 1 -0.99984

= 0.00016

c)P( 42 lesser than or equal to x lesser than or equal to 62)

= P(x lesser than or equal to 62) - P( x lesser than or equal to 40)

= 0.99987-0.2119= 0.78797

d) What yield strength value separates the strongest 75% from the others.

To get x for strongest 75, we get the z value corresponding to 0.75 from the table

z = 0.675= (x-44)/5

x = 3.375+44 = 47.375

The rest is 25% = 0.25

we get the z value corresponding to 0.25 from the table)

z = -0.67 = (x-44)/5

-3.35= x -44

x = -44+3.35= 40.65

yield strength value that separates the strongest 75% from the others

=47.375-40.65= 6.725

3 0

3 years ago

A random sample of 102 full-grown lobsters had a mean weight of 16 ounces and a standard deviation of 3.4 ounces. Construct a 98

pshichka [43]

Answer:

The best point estimate for a confidence interval estimating the population μ is 16 ounces.

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The best point estimate for a confidence interval estimating the population μ is

The sample mean, so 16 ounces.

T interval

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 102 - 1 = 101

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 101 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.98}{2} = 0.99$ . So we have T = 2.36

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.36\frac{3.4}{\sqrt{102}} = 0.79$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 16 - 0.79 = 15.21 ounces

The upper end of the interval is the sample mean added to M. So it is 16 + 0.79 = 16.79 ounces

The 98 percent confidence interval for the population mean μ is between 15.21 ounces and 16.79 ounces.

4 0

3 years ago

!TWELVE POINTS + BRAINLIEST ANSWER! Write the equation for an ellipse with y intercepts (0,-3) and (0, 3) and major axis of leng

Mandarinka [93]

Answer:

x²/25 + y²/9 = 1 or 9x² + 25y² = 225

Step-by-step explanation:

We have two points which is y intercepts (0,-3) and (0,3).

We know that the major axis is 2a and secondary axis is 2b

These two points are vertical top of the ellipse which they give us value of half secondary axis b = 3

The length of major axis is 2a = 10 => a = 10/2 = 5 => a = 5

The equation of the ellipse is:

x²/a² + y²/b² = 1 or b²x² + a²y² = a²b²

When we replace value of a and b we get:

x²/5² + y²/3² = 1 or 3²x² + 5²y² = 5² · 3² and finally

x²/25 + y²/9 = 1 or 9x² + 25y² = 225

God with you!!!

8 0

4 years ago