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Cloud [144]
2 years ago
14

9. An airline food service finds that a recent flight of 120 passengers ordered dinner as depicted in the table below. Based on

this data, how many lasagna dinners are likely to be needed for a flight with 380 passengers?
Dinner Frequency

Chicken 63
Fish 30
Lasagna 25
Vegetarian 2

A. 80 B. 85 C. 206 D. 301​
Mathematics
1 answer:
lina2011 [118]2 years ago
3 0

Answer:

80

Step-by-step explanation:

25/120 ( since you are trying to find probability of a situation)=.2083

.2083*380=79.167 (just round it off to the nearest 1 which is 80).

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A square with side length s has an area of 324 square centimeters. This equation shows the area of the square ^{s^2}is 324
svetlana [45]

Answer:

the side s is 18

Step-by-step explanation:

s=?

Area of square(A)=324

Now,

A=s²

324=s²

√(324)=s

s=18

5 0
2 years ago
85% of z is 106,250. What is z?
Lady bird [3.3K]

Answer:

z=12500

Step-by-step explanation:

Of means multiply and is means equals

85% *z = 106250

Change to decimal form

.85z = 106250

Divide each side by .85

.85z/.85 = 106250 /.85

z=12500

5 0
3 years ago
Read 2 more answers
3 7/8 convert to decimal
xxTIMURxx [149]

3 7/8 Converted into decimal equals 3.875


7/8 = 0.875 + 3

3 0
3 years ago
For a fundraiser, a committee decided to use a dice game. For the dice throwing game, you win twice the value of the number you
luda_lava [24]
It would possibly be $40
3 0
3 years ago
Question 4 please. I will mark brainliest!! i would at least like the equation of the graph thank you
Anestetic [448]

Answer:

a. -3 < x ≤ 5

b. -3 ≤ y < 3

c.  (0, 0)

d. x = -3, x = 1, x = 5

e. -3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. (-1, -1), and (3, -3)

Step-by-step explanation:

a. The domain of a function is the set of the possible independent variable values which is -3 < x ≤ 5

b. The range of a function is the set of the possible values of the dependent variable which is -3 ≤ y < 3

c. The y-intercept is the point the graph crosses the y-axis

The y-intercept in the graph is the point (0, 0)

d. f(x) ≥ 0  when x = -3, x = 1, x = 5

f(x) ≥ 0 over the following range; -3 < x ≤ - 1.5, 0 ≤ x ≤ 1.5, 4.5 ≤ x ≤ 5

e. The intervals over which f(x) is decreasing are;

-3 < x ≤ - 1, and 1 ≤ x ≤ 3,

f. The local minimums where f(x) has the minimum values are;

(-1, -1), and (3, -3)

3 0
3 years ago
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