At 08:00 there are 18 bags
At 08:10 there are an extra 10 produced = 28 but 1/2 are consumed leaving 14
At 08:20 there are an extra 10 produced = 24 but 1/2 are consumed leaving 12
At 08:30 there are an extra 10 produced = 22 but 1/2 are consumed leaving 11
At 08:36 another 6 have been produced = 17 bags
Assumed Correlation Value:
r1 = -0.5
r2 = 0.25
r3 = 0.90
r4 = 1
therefore,
r1 < r2 < r3 < r4
Letter A
Answer:
(a) ln(x) = 0
Then 0 < x < 1
(b) e^x > 2
Then ln2 < x < ∞
(a) ln(3x - 17) = 5
x = 55.1377197
ln(a + b) + ln(a - b) - 5ln(c)
= ln[(a² - b²)/c^5]
Step-by-step explanation:
First Part.
(a) ln(x) < 0
=> x < e^(0)
x < 1 ....................................(1)
But the logarithm of 0 is 1, and the logarithm of negative numbers are undefined, we can exclude the values of x ≤ 0.
In fact the values of x that satisfy this inequalities are between 0 and 1.
Therefore, we write:
0 < x < 1
(b) e^x > 2
This means x > ln2
and must be finite.
We write as:
ln2 < x < ∞
Second Part.
(a) ln(3x - 17) = 5
3x - 17 = e^5
3x = 17 + e^5
x = (1/3)(17 + e^5)
= 55.1377197
Third Part.
We need to write
ln(a + b) + ln(a - b) - 5ln(c)
as a single logarithm.
ln(a + b) + ln(a - b) - 5ln(c)
= ln(a + b) + ln(a - b) - ln(c^5)
= ln[(a + b)(a - b)/(c^5)]
= ln[(a² - b²)/c^5]
Step-by-step explanation:
4) 24/30=4/5
5) 2/24=1/12
6)14/84=1/6
7) 20/45=4/9
8)7/49=1/7
Hi I’m doing this for points
