Which term refers to the science that specifies the design and arrangement of items you use so you interact with the items effic
1 answer:
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Answer:
def compute_pay(number_of_hours, rate_of_pay):
if number_of_hours > 40:
pay_for_week = (40*rate_of_pay)+((number_of_hours-40)*\
(rate_of_pay+rate_of_pay*0.5))
else:
pay_for_week = number_of_hours*rate_of_pay
if pay_for_week >= 375:
print("Paying %d by direct deposit" % pay_for_week)
else:
print("Paying %d by mailed check" % pay_for_week)
Explanation:
- We define the computer pay function that receives the number of hours worked in a week and the rate of pay
- From the test cases we deduce that if a worker works more than 40 hours a week an extra payment is given, you can calculated it as follow: (40 * rate_of_pay) + ((number_of_hours - 40) * (rate_of_pay + rate_of_pay * 0.5))
- If a worker works less than 40 hours the payment is calculated as follow: pay_for_week = number_of_hours * rate_of_pay
- If the pay for week is equal or greater than 375 we print a payment by direct deposit otherwise we print payment by mailed check
Answer:
A and C
Explanation:
Option A:
In IPv6 there is a rule to reduce an IPv6 address when there are two or more consecutive segments of zeros just one time. This rule says that you can change the consecutive zeros for “::”
Here is an example
How to reduce the following IPv6 address?
ff02:0000:0000:0000:0000:0000:0000:d500
Ans: ff02::d500
Example 2:
2001:ed02:0000:0000:cf14:0000:0000:de95
Incorrect Answer -> 2001:ed02::cf14::de95
Since the rule says that you can apply “::” just one time, you need to do it for a per of zero segments, so the correct answer is:
Correct Answer -> 2001:ed02::cf14:0:0:de95
Or
2001:ed02:0:0:cf14::de95
Option C:
Since in IPv6 there are available addresses which means 340.282.366.920.938.463.463.374.607.431.768.211.456 (too many addresses), there is no need of NAT solution, so each device can have its own IP address by the same interface to have access through the internet if needed. If not, you can block the access through internet by the firewall.