True because if you were to bold a text, you have presented that the following text is more important or exemplified.
Answer:
i think its the second one
Explanation:
brainliest pls
Answer:
The correct answer to the following question is option "b".
Explanation:
The method having the same name but the arguments have different so it is called method overloading. It is a part of the object-oriented programming language (oops).
- In the given code we define same method two times that is "mystery()". but in this method, we pass two different parameters. For the first time, we pass a double variable that is "a" as a parameter. In the second time, we pass an integer variable that is "a" as a parameter and in both functions, we write some codes.
- In the calling time, we call function two times. In first time calling we pass an integer value that is "1" and second time calling we pass double value that is "1.0". So the output of this code is "int! double!".
That's why the option "b" is correct.
Answer:
I will code in JAVA.
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
boolean tallEnough;
boolean oldEnough;
Scanner input = new Scanner(System.in);
tallEnough = input.nextBoolean();<em> //wait the input for tallEnough</em>
oldEnough = input.nextBoolean(); <em>//wait the input for OldEnough</em>
if(tallEnough && oldEnough){
System.out.print(true);
} else {
System.out.print(false);
}
}
}
Explanation:
First, to accept user inputs you have to import the class Scanner. Then declare both variables before allowing the user to set input values for both boolean variables.
In the if-else statement checks if both variables are true, then prints true. Another case prints always false.
