6834/17 please show your work
1 answer:
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Answer:
B) To maintain peak performance for every 50 generators, there are 10 inspectors.
Step-by-step explanation:
For peak operational:
3 electricians for each generator. ⇒ 1 Generator : 3 Electricians
4 inspectors for every 60 electricians. ⇒ 60 Electricians : 4 Inspectors
Now, the number of generators the state has now = 50
Let us assume the number of inspectors required by the power plant = m
Now, from the given ratios:
For, 3 electrician there is 1 generator
⇒ For, 3 x 20 Electrician there is 1 x 20 Generators.
or, for 60 Electrician there are 20 Generators. (1)
Also, for 60 Electrician there are 4 inspectors. (2)
⇒From (1) and (2), we get:
For every 20 generators, there are 4 inspectors.
And, from what we have assumed For every 50 generators, there are m inspectors.
So, by the RATIO OF PROPORTION:
or, m = 10
Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.