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ArbitrLikvidat [17]
2 years ago
12

Can someone please compare and contrast 4 of the logarithmic functions and their inverse exponential functions ?

Mathematics
1 answer:
AysviL [449]2 years ago
3 0

Answer: Here is your answer: The Difference Between Logarithmic and Exponential. • The exponential function is given by ƒ (x) = e x, whereas the logarithmic function is given by g (x) = ln x, and former is the inverse of the latter. • The domain of the exponential function is a set of real numbers, but the domain of the logarithmic function is a set of positive real numbers.

Step-by-step explanation: Yw and mark me brainiest pls.

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Which graph shows the solution to this system of inequalities?<br><br> y&lt;-1/3x+1<br> y&lt;_2x-3
kari74 [83]

The graph that shows the solution to the system of inequalities is: C (see the image attached below).

<h3>How to Determine the Graph of the Solution to a System of Inequalities?</h3>

Given the following systems of inequalities:

y < -1/3x + 1

y ≤ 2x - 3

Below are the features of the graph that represents a solution to the system of inequalities:

  • The boundary line of y < -1/3x + 1 would be a dashed line and the shaded area would be below it, because of the inequality sign, "<".
  • The boundary lines of y ≤ 2x - 3 would be a solid line and the shaded area would be below it, because of the inequality sign, "≤".
  • The slope of the shaded line that represents  y < -1/3x + 1, would be -1/3, and the line would be a decreasing line which intersects the y-axis at 1.
  • The slope of the line that represents y ≤ 2x - 3, would be 2, and the line would also be an increasing line that intersects the y-axis at -3.

Therefore, the graph that shows the solution to the system of inequalities is: C (see the image attached below).

Learn more about the graph of the system of inequalities on:

brainly.com/question/10694672

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1 year ago
Sophie uses 16 beads to make a necklace. One fourth of the beads are purple. How many of the beads are purple?
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4/16 is 1/4 simplified.
So, 4 beads are purple.
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