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Serggg [28]
3 years ago
5

Inscribed angles math lib Need help with 9 and 10 thank you!!

Mathematics
1 answer:
telo118 [61]3 years ago
8 0

Answer:

54° and 110°

Step-by-step explanation:

The opposite angles of a cyclic quadrilateral are supplementary, sum to 180°

(9)

19x - 26 + 7x - 2 = 180

26x - 28 = 180 ( add 28 to both sides )

26x = 208 ( divide both sides by 26 )

x = 8

Then

∠ EFG = 7x - 2 = 7(8) - 2 = 56 - 2 = 54°

(10)

21x - 33 + 14x + 3 = 180

35x - 30 = 180 ( add 30 to both sides )

35x = 210 ( divide both sides by 35 )

x = 6

Then

∠ YVW = 14x + 3 = 14(6) + 3 = 84 + 3 = 87°

The inscribed angle YVW is half the measure of its intercepted arc YW, so

arc YW = 2 × 87° = 174°, then

arc XW = 174° - 64° = 110°

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Answer:

A. y=-5/3x+1

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solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation =  \sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}

Suppose,

     X             X - Xbar       (X - Xbar)^{2}

     3              3 - 6 = -3         -3 * -3 = 9

     5              5 - 6 = -1          -1 * -1 = 1

     10            10 - 6 = 4          4 * 4 = 16

<em>Mean of above data, Xbar</em> = \frac{3+ 5+10}{3} = 6

<em>Standard Deviation of data </em>= \sqrt{\frac{26}{3-1} } = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

     X                X - Xbar           (X - Xbar)^{2}

 3*2 = 6        6 - 12 = -6         -6 * -6 = 36

 5*2 = 10       10 - 12 = -2       -2 * -2 = 4

10*2 =20      20 - 12 = 8         8 * 8 = 64

<em>Mean of new data, Xbar </em>= \frac{6+ 10+20}{3} = 12

<em>Standard Deviation of new data</em> = \sqrt{\frac{104}{3-1} } = 7.2111

<em>Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as </em>

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Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

<em>And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.</em>

8 0
3 years ago
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