X^2-2x -3 =0
a =1 b =-2 and c = -3
x = - (-2) +/- sqrt (-2)^2 - 4(1)(-3)
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2(1)
x = + 2 +/- sqrt [(4) - 4(-3)]
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2
x = +2 +/- sqrt [4 + 12]
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2
x = +2 +/- sqrt[16]
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2
x = +2 +/- (4)
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2
x = 2 + 4 or 2 -4
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2 2
x = 6/2 or -2/2
x = 3 or x = -1
Answer:
the maximum number of crates that can be stacked between the floor and ceiling
where 1 foot = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.
Step-by-step explanation:
i) the maximum number of crates that can be stacked between the floor and ceiling
where 1 foot = 12 inches
Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.
Find the distance the bottom of the ladder is from the base of the wall.
Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is
0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is
14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.
Ensure that y ou have copied this problem accurately from the original.
I think it would be FGD and HGD
The correct answer choice is D.