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Goshia [24]
1 year ago
6

Expand the following expression: 4 (2k + j)

Mathematics
2 answers:
kotykmax [81]1 year ago
6 0

Answer:

  • \boxed{\sf{8k+4j}}

Step-by-step explanation:

Use the distributive property.

<u>Distributive property:</u>

⇒ A(B+C)=AB+AC

<h3>4(2k+j)</h3>

<u>First, multiply by expand.</u>

→ 4*2k=8k

→ 4*j=4j

<u>Rewrite the problem down.</u>

= 8k+4j

\Longrightarrow: \boxed{\sf{8k+4j}}

  • <u>Therefore, the correct answer is 8k+4j.</u>

I hope this helps! Let me know if you have any questions.

Nadya [2.5K]1 year ago
3 0

Answer:

4(2k + j) = 8k + 4j

Step-by-step explanation:

4(2k + j)

Distribute in the 4.

4 * 2k + 4 * j

Multiply 4 and 2k.

8k + 4 * j

Multiply 4 and j.

8k + 4j

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Step-by-step explanation:

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The mean yearly rainfall in Sydney, Australia, is about 134 mm and the standard deviation is about 66 mm ("Annual maximums of,"
svetlana [45]

Answer:

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Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 134, \sigma = 66

How many yearly mm of rainfall would there be in the top 15%?

At least X mm.

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3 years ago
What the value of 4x - 6y x=3 y=-2
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Answer:

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