Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
Answer:
0.75x
Step-by-step explanation:
Given that :
Discount rate= 25%
Original price = x
Discounted price of jacket :
(100 - discount rate)% * original price
(100 - 25)% * x
75% * x
0.75x
Answer:
a = E
b = A
c = B
d = D
I solved this using my graphic calculator.
Let's say that ST is side b
<span><span>Use the Law of Sines to find side b.</span><span>
b / sin(B) = a / sin(A)</span><span>
b / sin(59°) = 7 / sin(79°)</span><span>
b = (sin(59°) x 7) / sin(79°)</span><span>
b = 6.112
That is answer B.) 6.1 yards
Hope this helps!</span></span>
