How many groups of 5/6 are in 1
2 answers:
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Answer:
The concentration of the drug is 5ug/uL
Step-by-step explanation:
The first step of the problem is the conversion of the quantities of the drug in mg and mL to ug and uL.
In a rule of three problem, the first step is identifying the measures and how they are related, if their relationship is direct of inverse.
When the relationship between the measures is direct, as the value of one measure increases, the value of the other measure is going to increase too.
When the relationship between the measures is inverse, as the value of one measure increases, the value of the other measure will decrease.
Unit conversion problems, like this one, is an example of a direct relationship between measures.
First step: Conversion of 125mg to ug
Each mg has 1,000ug. So:
1mg - 1,000ug
125mg - xug
x = 1,000*125
x = 125,000 ug
Second step: Conversion of 25 mL to uL
Each mL has 1,000uL. So:
1mL - 1,000uL
25mL - x uL
x = 25*1,000
x = 25,000uL
Concentration:
The concentration of the drug is 5ug/uL
Answer:
a)
b) We need a sample of at least 282 young men.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?
To solve this problem, we use the 68-95-99.7 rule. This rule states that:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviations of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we want 99.7% of all samples give X within one-half inch of . So
must have
and
must have
.
So
(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?
You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that
The standard deviation of a sample of n young man is given by the following formula
We want to have
We need a sample of at least 282 young men.