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lisabon 2012 [21]
3 years ago
7

URGENT NEED THIS ASAP! 50 POINTS

Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

The Center is (-2 , 3)
Radius of the circle is 3

Step-by-step explanation:

x^{2}  + 4x + y^{2} - 6y = -4\\(x + 2)^{2}  + (y - 3)^{2}  = 9

∴ the center is ( -2, 3)

radius of thw circle is 3

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Find the slope of the line that passes through these points:
Deffense [45]
Use the slope formula:
         8-6
m = ------------ = ???
        -5-(-10)

6 0
4 years ago
How to do 314,207 in standard form??
olya-2409 [2.1K]
314 207 = 300 000 + 10 000 + 4 000 + 200 + 7
4 0
4 years ago
A point P lies on the line with equation y= 4-3X. The point P is a distance √34 from the origin. Find the two possible positions
Oksi-84 [34.3K]

The two possible positions of point P are:

(3, -5) and (0.6, 5.8)

<h3>How to find the two possible positions of point P?</h3>

We know that point P lies on the line:

y = 4 - 3*x

And that the distance between P and the origin is √34, then if the coordinates of point P are (x, y), we have that:

\sqrt{34} = \sqrt{x^2 + y^2}

Now, we can replace "y" in the distance equation by the linear equation, and also remove the square roots:

34 = x^2 + (4 - 3x)^2

Now we can solve the quadratic equation for x:

34 = x^2 + 9x^2 + 16 - 24x\\\\10x^2 - 24x - 18 = 0\\\\

The solutions are:

x = \frac{24 \pm \sqrt{(-24)^2 - 4*10*(-18)} }{2*10} \\\\x = \frac{24 \pm36}{20}

So the two solutions are:

x = (24 + 36)/20 = 3

x = (24 - 36)/20 = -0.6

To get the points, we need to evaluate y on these values:

y = 4 - 3*3 = -5   So we have P = (3, -5)

y = 4 - 3*(-0.6) = 2.2 So we have the point (0.6, 5.8)

There are the two possible positions of point P.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

#SPJ1

5 0
2 years ago
Two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube. One particle tra
zysi [14]

This shows that it will take the particle 23 secs to meet.

The distance travelled by each particle is 50cm

If two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube,

The first particle distances are 97cm, 93cm, 89cm... every 2secs

This form an arithmetic sequence and the nth term is expressed as:

Tn = a  + (n - 1)d

a is the first term = 97

d is the common difference = 4

Substitute

Tn = 97+(n - 1)(4)

Tn = 97 + 4n -4

Tn  = 4n  + 93

Similarly for the distances 49 cm, 47 cm, 45cm .....

This also forms an arithmetic sequence and the nth term is expressed as:

Tn = a  + (n - 1)d

a is the first term = 49

d is the common difference = 2

Substitute

Tn = 49+(n - 1)(2)

Tn = 49 + 2n -2

Tn  = 2n  + 47

For the particles to meet, this means that 4n  + 93 = 2n + 47

4n - 2n = 47 - 93

2n = -46

n = -23

This shows that it will take the particle 23 secs to meet.

To get the distance travelled by each particle

Tn  = 4n  + 93

T2 = 4(2) + 93

T2 = 101

For the other sequence;

Tn  = 2n  + 47

T2  = 2(2)  + 47

T2 = 51

Taking the difference;

D = 101 - 51 = 50cm

Hence the distance travelled by each particle is 50cm

Learn more here: brainly.com/question/13989292

3 0
3 years ago
Really confused about this
nasty-shy [4]

Answer:

.22/63

Step-by-step explanation:

area = pi x R^2

A=22/7 * 1/3^2

5 0
3 years ago
Read 2 more answers
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