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tino4ka555 [31]
2 years ago
6

An adjustable water ski ramp is set at the angles shown. An instructor wants to decrease angle x by 80.

Mathematics
1 answer:
almond37 [142]2 years ago
3 0

Answer:

22

Step-by-step explanation:

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What is 3 ^9? how to solve?
Tanya [424]
3⁹ is the same as doing:

3 * 3 * 3 * 3 * 3 * 3 * 3 * 3 * 3

What I would do it is narrow it down piece by piece. 

3 * 3 * 3 = 27. Do that 3 times, now you are left with:

27 * 27 * 27

27 * 27 or 27² = 729.

That leaves you with:

729 * 27

You can multiply by hand or use a calculator to get your answer of 19683.

To check your answer, plug 3⁹ into a calculator. Your answer should match this. 
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Answer:

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Step-by-step explanation:

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3 years ago
How to solve logarithmic equations as such
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\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
Leo wants to paint a moral that covers a wall with an area of 1440 sq ft. the height of the wall is 2 fifths of its length. What
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just took the test

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