All categories

3 years ago

3.95m + 8.95b = 47.65

Mathematics

1 answer:

nataly862011 [7]3 years ago

6 0

$3.95m + 8.95b = 47.65$ Equation

$\fbox{Solution for variable m}$

$3.95m=47.65-8.95b
$ $\text{Subtract 8.95b from both sides}$

$m= \dfrac{47.65-8.95b}{3.95}$ $\text{Divide both sides by 3.95}$

$\fbox{Solution for variable b}$

$3.95m + 8.95b = 47.65$ Equation

$8.95b=47.65-3.95m
$ $\text{Subtract 3.95m from both sides}$

$b= \dfrac{47.65-3.95m}{8.95}$ $\text{Divide both sides by 8.95}$

$\text{Hence Solved}$

You might be interested in

How to do this problem

insens350 [35]

Answer:

multiply 2 with the parenthesis

19-2m<7+8m-8

then you put a dot between -2 amd 3

Step-by-step explanation:

5 0

3 years ago

Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 500(1.075)120x = 100.000

Volgvan

Answer:

The solution is:

$x = 0.61$

Step-by-step explanation:

The first step to solve this equation is placing everything with the exponential to one side of the equality, and everything without the exponential to the other side. So

$500(1.075)^{120x} = 100000$

$(1.075)^{120x} = \frac{100000}{500}$

$(1.075)^{120x} = 200$

To find x, we have to apply log to both sides of the equality.

We also have that:

$\log{a^{x}} = x\log{a}$

$\log{(1.075)^{120x}} = \log{200}$

$120x\log{1.075} = 2.30$

$120x*0.03 = 2.30$

$3.77x = 2.30$

$x = \frac{2.30}{3.77}$

$x = 0.61$

4 0

3 years ago

Needing help ASAP with Algebra 1

mote1985 [20]

Answer:

yes plz ask the question what kind of help u need?

8 0

2 years ago

Read 2 more answers

Need help test coming soon can some help!?<br><br><br> Please

Paha777 [63]

Answer:

81 square metres is right anser follow me plse

4 0

2 years ago

Read 2 more answers

According to a recent survey, the population distribution of number of years of education for self-employed individuals in a c

creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

b) mean and the standard for a random sample of size 49

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4$

c) mean and the standard for a random sample of size 196

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2$

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0

3 years ago