3 years ago

The area of a square battlefield was 22,500 square miles. How long will it take a group of soldiers to cross the field diagonall

y at the rate of 3.2 miles/hour? Show work and explain

1 answer:

6 0

$\sqrt{22500} = s
\\\ diagonal = s \sqrt{2}
\\\ s = 150, \ diagonal = 150\sqrt{2}
\\\ diagonal \approx 212.132
\\\ 212.132/3.2 \approx 66.291 \ hrs$

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Triangle A B C is shown. Angle A C B is a right angle. The length of the hypotenuse is 20.

kherson [118]

Answer:

The length of BC is needed because it is the side opposite ∠A.

Step-by-step explanation:

Given the right angles triangle as shown in the attachment, we can get sin(A) without using Pythagoras theorem. Instead we will use SOH CAH TOA trigonometry identity.

According to SOH:

Sin(A) = Opposite/Hypotenuse

Sin(A) = |BC|/|AB|

Opposite side of the triangle is the side facing ∠A.

Based on the formula, we will need to get the opposite side of the triangle which is length BC for us to be able to determine sinA since the hypotenuse is given.