<h2>If AC = 8x-14 and EC = 2x +11, solve for x. %3D В A</h2>
Step 1
Given;

Required; To find the difference in interest between the two periods.
Step 2
State the formula for simple interest

Step 3
Find the interest when the rate is 8%

Therefore the interest is given as;

Step 4
Find the interest in 1980 with a 20% rate

The interest is given as;

Step 5
Find the difference in interest between the two rates.

Hence, the difference in interest between the two rates = $11095.89
Answer:
B and C
Step-by-step explanation:
(7 + 5i) - ( -9 + i)
= 7 + 5i - (-9) - (i)
= 7 + 5i + 9 - i
= 16 + 4i
= 4i + 16