20+2x/5-x
Start by writing it as a fraction
20 + 2/5x (fraction) - x
Next you calculate the difference
20 - 3/5x (fraction) is the answer
Answer:
The unit rate is accurately
(km/minute)
Step-by-step explanation:
(1,1/4) means that the vehicle traveled 1/4 km within 1 minute.
The unit rate for this problem is also known as the speed of the vehicle.
So to find the speed, you need to use distance over time.
---> Unit rate:
/ 1 =
(km/minute)
(2,1/2) means that the vehicle traveled 1/2 km within 2 minutes.
Same process:
---> Unit rate:
/ 2 =
Because of this, the unit rate is accurately
(km/minute)
Isosceles right triangles have two equal sides (a and b) that are not the hypotenuse (c). And when two sides are equal, so are their opposite angles. There are only 180° degrees in any triangles, thus the right angle = 90°, so 90 left for the two equal, means that 2x=90,
x = 45°.
There are several ways to go about solving a triangle like this. The best and easiest is simply to memorize that the hypotenuse is exactly root2 times the other sides. Or, each isosceles side is the hypotenuse (c) ÷ root2
![a = b = c \div \sqrt{2} \\ c = a\sqrt{2} \\ c = 6 \sqrt{2} \times \sqrt{2} = 6 \times 2 = 12](https://tex.z-dn.net/?f=a%20%3D%20b%20%3D%20c%20%5Cdiv%20%20%5Csqrt%7B2%7D%20%5C%5C%20c%20%20%3D%20a%5Csqrt%7B2%7D%20%20%5C%5C%20c%20%3D%206%20%5Csqrt%7B2%7D%20%5Ctimes%20%5Csqrt%7B2%7D%20%20%3D%206%20%5Ctimes%202%20%3D%2012)
Another way to do it is the longer proof of Pythagorean Theorem:
![{c}^{2} = {a}^{2} + {b}^{2}... \: \: c = \sqrt{({a}^{2} + {b}^{2})} \\](https://tex.z-dn.net/?f=%20%7Bc%7D%5E%7B2%7D%20%20%3D%20%20%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D...%20%5C%3A%20%20%5C%3A%20%20c%20%3D%20%20%20%5Csqrt%7B%28%7Ba%7D%5E%7B2%7D%20%20%2B%20%20%7Bb%7D%5E%7B2%7D%29%7D%20%20%5C%5C%20)
The correct answer is <span>1 and 1/2
Hope I helped</span>
Step-by-step explanation:
The complete frequency distribution table for the data has been attached to this response.
The frequency column contains values that are the number of times the given range of hours appear in the data. For example, numbers in the range 0 - 2 hours, appear <em>9</em> times in the data. Also, the numbers in the range 3 - 5 appear <em>6</em> times. The same logic applies to other ranges.
The relative frequency column contains the ratio of the number of times the given range of hours appear in the data, to the total number of outcomes. The total number of outcomes is the sum of all the frequencies on the frequency column. This gives 38 as shown.
So, for example, to get the relative for the numbers in the range 0-2, divide their frequency (9) by the total outcome or frequency (38). i.e
9 / 38 = 0.24
Also, to get the relative for the numbers in the range 3-5, divide their frequency (6) by the total outcome or frequency (38). i.e
6 / 38 = 0.16
Do the same for the other ranges.