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Gnoma [55]
3 years ago
5

7-5x+1 please answer i need this NOW!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
Alisiya [41]3 years ago
5 0

Answer:x=8/5 or 1.6

​​  

Step-by-step explanation:

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OAB is a sector of a circle of radius 12 cm Angle AOB= 60º Work out the length of the arc B. Give your answer in terms of pie.
Debora [2.8K]

Answer:

Since 60° is one sixth of the entire circle (360°) it means that the length of arc B is 1/6 th of the circumference.

1/6 * (12 * 2π) = 4π

3 0
3 years ago
John want to simplify the expression (5 + 3) (With the power of 2). As a first step, he writes 5( with a power of 2) + 3( With a
professor190 [17]

5^2 + 3^2 (equals to 34) ; That's the wrong expression

It should look like this : (5+3)^2 (which equals to 64)

4 0
2 years ago
Over three days I earn 2568. On the first day I made twice as much as the second day. On the third day I made three times as muc
Fudgin [204]

Answer:

<em>I earned $856 on the first day</em>

Step-by-step explanation:

Let's call

x = earning on the second day

2x = earnings on the first day

3x = earnings on the third day

The total earnings are $2568, thus

x + 2x + 3x = 2568

Simplifying:

6x = 2568

Dividing by 6:

x = 2568/6

x = 428

I earned $428 on the second day.

2x = 2*$428 = $856

I earned $856 on the first day

8 0
2 years ago
(Answer the given using PRB with the formula and pls give the full solution!!! )
juin [17]

Answer:

hoskina g to the people ina this contry

4 0
2 years ago
Find cos(2*ABC) 100POINTS
juin [17]

Answer:

-\dfrac{7}{25}

Step-by-step explanation:

<u>Trigonometric Identities</u>

\cos(A \pm B)=\cos A \cos B \mp \sin A \sin B

<u>Trigonometric ratios</u>

\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Using the trig ratio formulas for cosine and sine:

  • \cos(\angle ABC)=\dfrac{3}{5}
  • \sin(\angle ABC)=\dfrac{4}{5}

Therefore, using the trig identities and ratios:

\begin{aligned}\implies \cos(2 \cdot \angle ABC) & = \cos(\angle ABC + \angle ABC)\\\\& = \cos (\angle ABC) \cos (\angle ABC) - \sin(\angle ABC) \sin (\angle ABC)\\\\& = \cos^2(\angle ABC)-\sin^2(\angle ABC)\\\\& = \left(\dfrac{3}{5}\right)^2-\left(\dfrac{4}{5}\right)^2\\\\& = \dfrac{3^2}{5^2}-\dfrac{4^2}{5^2}\\\\& = \dfrac{9}{25}-\dfrac{16}{25}\\\\& = \dfrac{9-16}{25}\\\\& = -\dfrac{7}{25} \end{aligned}

7 0
2 years ago
Read 2 more answers
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