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Nookie1986 [14]

2 years ago

12

The formula below is used to convert a tempreture in degrees Farenheit,F to a tempreture in degrees Celsuis ,C.C = 5/9 (f-32) Wh

at is the tempreture in degrees celsuis that is equivalent to a tempreture of 40f?

1 answer:

spayn [35]2 years ago

6 0

Answer:

4.4 degrees C.

Step-by-step explanation:

C = 5/9 (F - 32)

When F = 40:

C = 5/9( 40 - 32)

= 5/9 * 8

= 40/9

= 4.4 degrees C,

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Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago

Mary bought 4 small cookies for 40 cents each and 2 large cookies for 90 cents each how much did she spend all together

babunello [35]

Answer:

$3.40

Step-by-step explanation:

4x.40 is 1.60

2x.90 is 1.80

Then you take 1.80+1.60 to get $3.40 Hope this helps!

4 0

3 years ago

Using all of the following numbers once, 8,8,3,5 how do u get 10

Sveta_85 [38]

Lol this is hard try using multiplication or division...

8 0

3 years ago

If you want to buy an item in a store that cost $43 and is on sale for 40% off, then how much would the item actually cost you a

expeople1 [14]

Answer:

$25.80

Step-by-step explanation:

40% = 40/ 100 = 4/10 = 0,4

There is a 40% discount, which means that the amount multiplied by more then 1 (for example 1,4) would increase the amount... That isn't right because it is a discount!

So you need to subtract the 40%, so (1 - 0.4 =) 0.6

The amount multiplied by 0.6 will be the correct amount, being $43 * 0.6 = $25.80 (rounded to the nearest cent).

The amount the item actually cost after the discount is $25.80

4 0

3 years ago

When a bactericide is added to a nutrient broth in which bacteria are growing, the bacteria population continues to grow for a

baherus [9]

Answer:

a) 1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t is given by:

$b(t) = 9^6 + 6^4t-6^3t^2$

We differentiate the given function.

Thus, the growth rate is given by:

$\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t$

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$\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}$

b) Growth rates at t = 3 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}$

c) Growth rates at t = 6 hours

$\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}$

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4 years ago