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Blizzard [7]
3 years ago
6

What must be different for a system to have one solution

Mathematics
1 answer:
dangina [55]3 years ago
6 0
For two-variable systems<span>, there are then three possible types of </span>solutions<span>: ... This shows that a </span>system<span> of equations may </span>have one solution<span> (a specific x,y-point)</span>
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A soup bowl is in the shape of a hemisphere with a diameter of 10 cm. What is the approximate maximum volume of soup that the bo
Oduvanchick [21]

Answer:

3.48cm³ (approximated)

Step-by-step explanation:

The maximum water that bowl can hold = The volume of the bowl

\boxed{ \mathsf{volume \: of \: bowl =  \frac{2}{3}  \times \pi \: r {}^{3} }}

Radius is half of diameter.

<u>Given</u> -

  • Diameter = 10cm .

<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>

Putting the known values into the formula to get the value of the volume of bowl :

\mathsf{volume =  \frac{2}{3} \times \:   3.14 \:  \times  {5}^{3} }

= 3.48888cm³

= 3.48cm³

5 0
2 years ago
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