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Nikitich [7]
3 years ago
13

A circle is graphed with its center on the origin.The area of the circle is 49 square units.What are the coordinates of the x-in

tercepts of the graph? Round to the nearest tenth
Mathematics
1 answer:
neonofarm [45]3 years ago
3 0

Answer:

3.95 and -3.95

Step-by-step explanation:

To graph a circle you can use the formula or (x – h)^2 + (y – k)^2 = r^2. So substituting in the given, we get x^2+y^2=49/pi. The x intercept is when y=0. So x^2=49/pi and so

x = sqrt(49/pi) and rounding to the nearest tenth, we get 3.95 and -3.95 because it isn’t a principal square root.

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Write the radical below in the simplest radical form<br><br> √210 <br><br> Pls show ur work
Anna [14]

Answer:

\sqrt{210}

Step-by-step explanation:

Let's look at the prime factors of 210.

210 = 2 * 3 * 5 * 7

\sqrt{210} = \sqrt{2 \times 3 \times 5 \times 7} = \sqrt{210}

Since no factor appears more than once, this radical cannot be simplified.

3 0
3 years ago
Write an equation of the line that passes through (-4, 1) and is parallel to the
LiRa [457]

Answer:

y-1=2(x+4) or y=2x+9

Step-by-step explanation:

y - 3 = 2(x + 7)

y=mx+b

m=2

(x1,y1) -> (-4, 1)

(y−y1)=m(x−x1)

plug in

y-1=2(x+4)

y-1=2x+8

y=2x+9

test:

(1)=2(-4)+9

1=-8+9

1=1

4 0
3 years ago
Company A charges a base rate of $5 per month, plus 4 cents per minute that you are on the phone. Company B charges a base rate
Afina-wow [57]

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4 0
3 years ago
Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,
Sholpan [36]
A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
d^2=3^2+2^2
d^2=9+4
d^2=13
d= \sqrt{13}
We can conclude that the distance between my house and the movie theater is \sqrt{13}

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
d^2=6^2+5^2
d^2=36+25
d^2=61
d= \sqrt{61}
We can conclude that the distance between the police station and the airport is \sqrt{61}

C. Distance form the park to the Fire Station:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance from the park to the Fire Station is \sqrt{10}

Distance from the stadium to the mall:
d^2=2^2+1^2
d^2=4+1
d^2=5
d= \sqrt{5}
We can conclude that the distance from the stadium to the mall is \sqrt{5}

D. What is the distance between your house and the mall?
Answer:
d^2=4^2+4^2
d^2=16+16
d^2=32
d= \sqrt{32}
d=4 \sqrt{2}
We can conclude that the distance between my house and the mall is 4 \sqrt{2}

What is the distance between the movie theater and the school?
answer:
d^2=3^2+1^2
d^2=9+1
d^2=10
d= \sqrt{10}
We can conclude that the distance between the movie theater and the school is \sqrt{10}

7 0
3 years ago
Pls help asap MIDSEGMENTS
Salsk061 [2.6K]

Answer:

RT and KS

Step-by-step explanation:

isosceles triangle

3 0
3 years ago
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