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avanturin [10]
1 year ago
15

What is the completely factored form of p4 – 16? (p – 2)(p – 2)(p 2)(p 2) (p – 2)(p – 2)(p – 2)(p – 2) (p minus 2) (p 2) (p squa

red 2 p 4) (p minus 2) (p 2) (p squared 4)
Mathematics
1 answer:
n200080 [17]1 year ago
3 0

The completely factored form of the provided polynomial is  (p -2) (p+ 2) (p² +4). The option 4 is the correct option.

<h3>What is polynomial?</h3>

Polynomial equations is the expression in which the highest power of the unknown variable is n (n is a real number).

The polynomial equation given in the problem is,

p^4 - 16

Let the factor form of the polynomial is f(p). Thus,

f(p)=p^4 - 16\\f(p)=p^4 - 2^4\\f(p)=(p^2)^2- (2^2)^2

Using the formula of difference of squares, we get,

f(p)=(p^2-4)(p^2+4)\\f(p)=(p^2-2^2)(p^2+4)\\f(p)=(p-2)(p+2)(p^2+4)

Thus, the completely factored form of the provided polynomial is  (p -2) (p+ 2) (p² +4). The option 4 is the correct option.

Learn more about polynomial here;

brainly.com/question/24380382

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On a biased dice , the probability of getting a 6 is 4/5. The dice is rolled 500 times. How many sixes would you expect to roll?
tatyana61 [14]

Find 4/5 of 500.

4/5*500=400

You will roll 400 sixes.

5 0
3 years ago
Please assist me with this problem​
n200080 [17]

Answer:

The answer to your question is 90 dB

Step-by-step explanation:

Data

I = 10⁻³

I⁰ = 10⁻¹²

Formula

     Loudness = 10log (\frac{I}{Io})

Process

1.- To solve this problem, just substitute the values in the equation and do the operations.

2.- Substitution

     Loudness = 10 log (\frac{10^{-3}}{10^{-12}} )

3.- Simplify

      Loudness = 10log (1 x 10⁹)

      Loudness = 10(9)

      Loudness = 90

7 0
2 years ago
Mason invested $65,000 in an account paying an interest rate of 4.6% compounded
Advocard [28]

Answer:

t≈17

Step-by-step explanation:

8 0
2 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
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