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2 years ago

How would larger substances like proteins get into or out of the cell membrane?

Biology

1 answer:

spin [16.1K]2 years ago

7 0

Answer:

It is possible for large molecules to join a cell by a method called endocytosis, where a small piece of the cell membrane surrounds the particle and is brought into the cell. If the particle is solid, endocytosis is also dubbed phagocytosis. If fluid droplets are taken in, the process is called pinocytosis.

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Will the sun eventually become a neutron star?

qaws [65]

answer:

our sun will never become a neutron star.

explanation:

neutron stars are born from suns that are 10-20 times the size of ours.
in 5 billion years our sun will become a red giant and then eventually a cold white dwarf which is similar to a neutron star, just much larger and much less dense.

5 0

3 years ago

What are the mechanisms of natural selection, and how do they lead to changes in

Nata [24]

Darwin's proposed mechanism for evolution is natural selection. Natural selection allows species to respond to their surroundings through time, or to become progressively excellently-suited. Natural selection is environmentally based and involves established heritable variation within a population.

They lead to changes in species over time:

Darwin suggested species will evolve over time, new species originate from pre-existing species, and all species share a common ancestor with each other.
In this framework each organism has its own special set of heritable i.e genetic variations from the common ancestor that have slowly developed over very longer periods of time.
Parroted branching activities that isolate new species from a common ancestor create a multi-level tree that connects all living organisms.

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3 years ago

People tint windows dark to encourage __________.

suter [353]

Absorption is the correct answer

7 0

2 years ago

Read 2 more answers

The process by which evolution occurs is called

Stella [2.4K]

Answer: natural selection

3 0

3 years ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

4 0

2 years ago